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C.  Answer the following questions:
                  1.  Draw the truth table of (i) conditional (ii) biconditional
                Ans.   a    b    a → b   a ↔ b
                       0    0      1       1
                       0    1      1       0
                       1    0      0       0
                       1    1      1       1
                  2.  Draw the logic circuit diagram of the following Boolean expressions using AND, and OR gates. Assume complement is available
                    as input.
                     (i)  (B'+D).(A'+D').(B+C'+D')               (ii) (B'.C'+A.C)'

                Ans.  (i)
                       B'            (B'+D)
                       D


                       A'            (A'+D')              (B'+D).(A'+D').(B+C'+D')

                       D'


                       B
                       C'           (B+C'+D')
                       D'

                      (ii)
                       B'               B'.C'
                       C'
                                                         (B'.C'+A.C)'


                       A

                       C                A.C

                  3.  Draw a logic circuit diagram to represent AND, OR and NOT gates using NOR gate only.
                Ans.  (i)  NOT gate using NOR gate
                                             A                (A+A)'                 A'           (A+A)'

                                             A                                                    =A'

                    (ii)  OR gate using NOR gate

                                             A               (A+B)'                 (A+B)         = ((A+B)')'
                                             B                                                    = (A + B)

                     (iii)  AND gate using NOR gate
                                             A                  A'

                                             A                                                    (A'+B)')'
                                                                                    A.B
                                                                                                  = A" . B"
                                                                                                  = A . B
                                             B                  B'
                                             B



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