Page 196 - Computer Science Class 11 With Functions
P. 196

6.    min(<sequence>)                 Returnonthenomalleotn    >>> lst=[3, -2, 0, 78, 25]

                   or                              argumentnfromnanliot,n   >>> min(lst)
                                                   tuple,nornoequencenofn       -2
                   min(<val1,val2,...,valn>)
                                                   argumento.               >>> min(2,0,-4,19,36,8)
                                                                                -4
                                                                            >>> min((6, 7, 4))
                                                                                4
                                                                            >>> min(59, 80, 95.6, 95.2)
                                                                                59
             7.    divmod(<num1,num2>)             Returnonantuplencomprioingn >>> divmod(17,4)
                                                   Quotentn andn remaindern      (4, 1)
                                                   whenn num1n ion dividedn byn  >>> divmod(-21,5)
                                                   num2.                        (-5, 4)
             8.    sum(<sequence [,num2]>) Returnon         oumn   ofn  alln >>> lst =[1, 3, 5, 7]
                                                   numericn valueon inn then >>> sum(lst)
                                                   givenn inputn oequence.n     16
                                                   Optonaln inputn num2,n >>> sum(lst,5)
                                                   whennprovided,nionaddedn     21
                                                   tonthenoumnofnelementonofn >>> sum((1, 3, 5, 7))
                                                   thenoequence.                16
                                                                          n
             9.    abs(num)                        Aboolutenvaluenofninteger,n >>> abs(-12)
                                                   floatng-point,norncomplexn      12
                                                   number.                  >>> abs(-14.7)
                                                                                14.7
                                                                            >>> abs(21)
                                                                                21
                                                                            >>> abs(4+3j)
                                                                                5.0
             10.   pow(num1, num2[,num3])          Returnon num1n raioedn >>> pow(14, 3)
                                                   ton then powern ofn num2.n      2744
                                                   Optonaln input,n num3,n  >>> pow(3, 4, 5)
                                                   whennprovided,nionuoednforn      1
                                                   computatonn aon followo:n  >>> pow(-2.3, 5)
                                                                                -64.36342999999998
                                                   (num1**num2)%num3
                                                                            >>> pow(2, 5, 3)
                                                                                2
             11.   round(num[, digits])            Roundon then givenn inputn >>> round(10.6)
                                                   numbern numn ton then        11
                                                   neareotn integern orn upn ton  >>> round(13.8907, 2)
                                                   then opecifiedn precioionn      13.89
                                                   (digits)n aftern then    >>> round(-12.0456, 3)
                                                   decimalnpoint.               -12.046












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