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19.  Subtract the given hexadecimal numbers (9A78.25)  - (FAD.50)  using:
                                                            16
                                                                     16
                      a. Borrow method
                      b. 15’s complement method
                      c.  16’s complement method
                Ans.  a.           +16    +16   +16     +16

                             9   8  A    9  7   6  8    7  .  2  5
                         -          F      A     D    .   5    0
                              8     A      C     A    .  D     5
                           (8ACA.D5) 16
                     b. 15’s complement of  0FAD.50  is F052.AF  +1                         +1
                       Adding 9A78.25 and F052.AF, we get             9    A    7    8   .   2    5
                        (8ACA.D5)                           +         F    0    5    2   .   A    F
                               16
                                                                 1    8    A    C    A   .   D    4
                                                                                                  1
                                                                      8    A    C    A   .  D     5

                     c.  15’s complement of  0FAD.50  is F052.AF  +1
                       16’s complement of F052.AF is F052.B0          9    A    7    8   .   2    5
                       Adding 9A78.25 and F052.B0, we get   +         F    0    5    2   .   B    0
                       Ignoring MSB 1, we get                    1    8    A    C    A   .  D     5
                        (8ACA.D5) 16

                 20.  Subtract (1B7)  - (8D27)  using:
                                        16
                                16
                      a. 15’s complement method
                      b. 16’s complement method
                Ans.  a. 15’s complement of 8D27 is 72D8              +1
                       Adding 1B7 and 72D8, we get                    1     B    7
                        15’s complement of 748F is 8B70     +    7    2     D    8
                        (-8B70) 16                               7    4     8     F
                      b. 15’s complement of 8D27 is 72D8              +1    +1
                        16’s complement of 72D8 is 72D9               1     B     7
                       Adding 1B7 and 72D9, we get 7490     +    7    2     D     9
                        15’s complement of 7490 is 8B6F          7    4     9     0
                        16’s complement of 8B6F is 8B70
                        (-8B70) 16
                 21.  Perform the following Octal multiplication:
                      a. 52  × 33                                b. 170  × 44
                         8   8                                        8   8
                Ans.            5    2                                         1   7    0
                            x   3    3                                         x   4    4
                           +1                                                 +3
                                7    6                                         4   4    0
                      +1                                                 +3
                            7   6    x                                    4    4   0    x
                       2    1   5    6                               1    0    3   4    0

                      2156 8                                         10340 8





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