Page 201 - Ganit Kaushal
P. 201

13       1
                     Ex:  Find equivalent fractions for the fractions    and     such that the fractional units are the same.
                                                                     6       9                                    (NCERT)
                    Sol.  LCM of denominators (6, 9) = 2 × 3 × 3 = 18.
                          So, we multiply the numerators and denominators of both the fractions by suitable numbers,   2 6, 9
                          so that the denominator of both fractions becomes 18.                                    3 3, 9
                                                  ×
                                          13   13 3     39      1    12      2                                     3 1, 3
                                                                      ×
                          We can do it as:    =       =     and   =       =                                          1, 1
                                          6     63      18      9    9 ×  2  18
                                                  ×
                            39       2                               13      1                                        1
                         ∴      and     are the fractions equivalent to    and   respectively with the same unit fraction  .
                            18      18                                6      9                                       18
                                                            Solved Examples
                    Ex 1.  Express the following as mixed fractions:
                             20                     11                       17
                         (a)                    (b)                      (c)
                              3                      5                        7

                             20        6                                     11       2
                    Sol. (a)    ,   3 20                                 (b)    ,   5 11
                              3      –18                                     5      –10
                                       2                                              1
                               [ Here, quotient = 6 and remainder = 2]           [ Here, quotient = 2 and remainder = 1]

                                 20     2                                        11    1
                              So,   =  6                                     So,   =  2
                                  3     3                                        5     5
                                        2
                             17     7 17
                         (c)    ,                                                 [ Here, quotient = 2 and remainder = 3]
                              7       –14
                                        3
                                 17     3
                              So,   =  2
                                 7     7
                    Ex 2.  Express the following mixed fractions as improper fractions:

                         (a)   7  3             (b)   5 6                (c)  2  5               (d)  10 3
                               4                      7                        6                       5
                    Sol.  We convert a mixed fraction into an improper fraction by using the formula given in section 7.3.
                                                                                     ×
                                                                                        )
                                        )
                                                   +
                               3   ( 7 ×  4 + 3  28 3   31                    6   ( 57 +   6   35 +  6  41
                         (a)  7  =            =       =                  (b)  5 =            =        =
                               4       4          4      4                    7        7          7      7
                                  (An improper fraction)                          (An improper fraction)
                               5
                                     ×
                                                                                       ×
                                                                               3
                                                                                          )
                                        )
                         (c)   2 =  ( 26 +  5  =  12 +  5  =  17         (d)   10 =  ( 10 5 +  3  =  50 +  3  =  53
                               6       6          6      6                     5        5          5      5
                                  (An improper fraction)                          (An improper fraction)
                    Ex 3.  Find equivalent fractions for the given pairs of fractions, such that their fractional units are the same.
                             9      5                1      2                8 11       13
                         (a)    and             (b)     and              (c)   ,    and
                             4      2               10      9                3   4      6
                                                      5    52     10
                                                             ×
                    Sol. (a)  LCM of 4, 2 = 4.    ∴      =      =
                                                             ×
                                                      2    22      4
                                 9      10                           9      5                              1
                              So,   and     are fractions equivalent to   and  with the same fractional unit  .
                                 4       4                           4       2                             4
                                                                                                         Fractions    199
   196   197   198   199   200   201   202   203   204   205   206