Page 202 - Ganit Kaushal
P. 202

×
                                                   1    19       9      2    210     20
                                                          ×
                     (b)  LCM of 10, 9 = 90.  ∴      =        =     and  =         =    .
                                                                              ×
                                                  10    10 9    90      9    910     90
                                                          ×
                              9      20                             1      2                               1
                          So,    and      are fractions equivalent to    and   with the same fractional unit   .
                             90      90                            10      9                              90
                                                                          ×
                                                         ×
                                                   8   84      32 11    11 3    33      13  13 2    26
                                                                                               ×
                     (c)  LCM of 3, 4, 6 = 12.  ∴    =       =   ,    =       =     and    =      =
                                                         ×
                                                   3   34     12    4   43      12       6   62     12
                                                                          ×
                                                                                               ×
                             32 33        26                           8 11       13                              1
                          So,   ,    and      are fractions equivalent to  ,    and    with the same fractional unit   .
                             12 12        12                           3   4       6                              12
                                                    3
                Ex 4.  Find the equivalent fraction of   having:
                                                    5
                     (a)  a denominator of 20.                       (b)  a numerator of 9.
                                                                              ×
                          3  34     12                                   3   33     9
                               ×
                Sol. (a)   =      =                                  (b)   =      =
                               ×
                          5  54     20                                   5   53 15
                                                                              ×
                Ex 5.  Find the equivalent fraction of   77   having:
                                                    63
                     (a)  a denominator of 18.                       (b)  a numerator of 33.
                Sol.  Here, we first convert it to the simplest form. HCF (77, 63) = 7 and dividing by the HCF, we get
                                                              ÷
                                                      77  =  77 7  = 11  (Simplest form)
                                                              ÷
                                                      63   63 7     9
                     (a)  Now, multiply both the numerator and the denominator by 2 to get 18 in the denominator i.e.,
                                  ×
                         11  =  11 2  =  22 . This fraction is equivalent to   77  and has a denominator of 18.
                                 ×
                          9     92     18                               63
                     (b)  Now, to get the numerator 33, multiply both the numerator and the denominator of the simplest
                               11
                         form     by 3.
                               9
                                        ×
                                   =
                          We get  11 11 3  =  33 . This fraction is equivalent to  77   and has a numerator of 33.
                                 9    93     27                               63
                                       ×
                Ex 6. (a)  Anil was in a group where 2 cakes were divided equally among 5 children. How much cake would
                         Anil get?
                     (b)  Now, if there are 10 children in Anil’s group, how many cakes will Anil need so that they get the
                         same amount of cake as Anil?
                     (c)  What share will each get if we put two such groups together? One group where 2 cakes are divided
                         equally among 5 children, and another group, again with 4 cakes and 10 children.     (NCERT)
                                                                              2
                Sol. (a)  2 cakes are divided into 5 equal parts. ∴ Anil will get   of the total cake.
                                                                              5
                                                                                                 2
                     (b)  To get the same amount of cake, we need to find an equivalent fraction to   with a denominator
                         of 10.                                                                  5
                                 2   22     4
                                      ×
                          We get  =       =
                                 5   52     10
                                      ×
                          ∴ The number of cakes needed = 4.
                     (c)  Here the total number of cakes = 2 + 4 = 6

                          Total number of children = 5 + 10 = 15.
                                                 6     2
                          ∴ Each child will get =    =    of the total cake.
                                                 15    5


              200     Mathematics-6
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