Page 209 - Ganit Kaushal
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1      1
                    Ex 2.   Find the sum of   and   using Brahmagupta’s method.                                   (NCERT)
                                          6      3
                                                                     1
                                                       1
                                                                            1
                                                                                 ×
                    Sol.  The LCM of 6 and 3 is 6. So,   will remain   and  =   12   =  2  .
                                                       6             6      3   32     6
                                                                                  ×
                                                        ÷
                                   1   1   1   2   3   33     1
                        Therefore,  +    =   +   =   =      =     [simplest form]
                                                        ÷
                                   6   3   6   6   6   63     2
                                           1   1  1
                    Ex 3.  Find the value of  +− .
                                           4   3  2
                    Sol.  The LCM of 2, 3 and 4 = 12. So, we can make the denominator of each fraction equal to 12 by
                          multiplying and dividing it by a suitable number. We get
                                        1  +−  1  =  13  + 14  −  16   =  3  +  4  −  6  =  34 6  =  1
                                                                   ×
                                            1
                                                            ×
                                                                                        +−
                                                     ×
                                                                   ×
                                                     ×
                                                            ×
                                        4   3  2   43     34     26     12 12 12          12     12
                  Addition and Subtraction of Mixed Fractions
                  To add or subtract mixed fractions, first convert them into improper fractions and then add or subtract them as
                  explained in Brahmagupta’s Method.
                  For example:
                         3    1   13  8   13 7     85     91   40   91 40     131     26
                                                                       +
                                             ×
                                                    ×
                    (i)  2 + 1 =     +  =        +      =    +    =         =     = 3
                         5    7   5   7    57      75     35   35      35      35     35              Note
                                                     ×
                                             ×
                                                                                       5
                                                                         −
                                              ×
                                                      ×
                         1    1   13 16    13 5 16 3        65   48   65 48     17     2
                    (ii)  4 − 3 =    −    =       −       =    −    =         =    = 1              4 can be written as   4
                                              ×
                                                      ×
                                                                                       5
                         3    5   3    5    35      53      15   15     15      15    15                              1
                                                                    ×
                                                                             −
                                                                                 +
                                                            ×
                         2    1      17   7   4   17 ×  3  75     415     51 35 60      76          and LCM (5, 3, 1) = 15.
                   (iii)  3 − 2 + =     − +     =       −       +       =             =
                                  4
                                                            ×
                                                                                         5
                                                    ×
                                                                   ×
                         5    3       5   3   1    53     35      115          15       15
                  7.7 MULTIPLICATION OF FRACTIONS
                  Two or more fractions can be multiplied just by multiplying the numerators and their denominators. If mixed
                  fractions are involved, we need to convert them to improper fractions first and then multiply. Finally convert
                  the result to simplest/least form, if required.
                                           ×
                                5   11   511      55    2   5   8   5   40   40 ÷  2  20
                  For example:    ×    =        =   ;  2  ×   =  ×   =     =       =      (after converting to least form)
                                7   13   713      91    3   6   3   6  18    18 ÷  2  9
                                           ×
                  Two fractions are said to be the reciprocals of each other if their product is 1.
                                13   11   13 11                 11      13
                                             ×
                  For example:     ×    =        = 1. Therefore     and     are reciprocals of each other.
                                11   13   11 13                 13      11
                                             ×
                  The reciprocal of a fraction can also be obtained just by interchanging its numerator and denominator.
                                                            Solved Examples
                    Ex 1.  Add the following fractions using Brahmagupta’s method:                                (NCERT)
                             2   5   6              2   4                    3   1  1
                         (a)   +   +            (b)   +                  (c)   ++
                             7   7   7              3   5                    4   3  5
                               ++
                    Sol. (a)   256    =  13    [ In like fractions, just add the numerators keeping the denominator the same]
                                 7       7
                                                                                                         Fractions    207
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