Page 211 - Ganit Kaushal
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2                                   3
                    Ex 5.  Geeta bought   metre of lace and Shamim bought   metre of the same lace to put a complete border
                                       5                                   4
                          on a tablecloth whose perimeter is 1 metre long. Find the total length of the lace they both have bought.
                          Will the lace be sufficient to cover the whole border?                                  (NCERT)
                                                                  4 35
                                                      2   3   2 ×+     ×    815      23     3
                                                                              +
                    Sol.  The total length of the lace =  +  =            =        =    = 1    metres
                                                                   ×
                                                      5   4       54          20     20    20
                            Yes, the lace will be sufficient to cover the whole border because it is more than one metre.
                    Ex 6.  Complete the adjoining addition-subtraction box.
                                        2   4   6     1   2   3                                                2    4
                    Sol.  We have,        +   =   =  2,  +  =   = 1,                                           3    3
                                        3   3   3     3   3   3                                                1    2
                                                  −
                                                       1 4
                                                                   −
                                        2  −=   21   = ,   −  2  =  42  =  2  ,                                3    3
                                            1
                                        3   3    3     3 3   3     3     3
                                        1   2   12     3
                                                 +
                          and             +   =      =   = 1
                                        3   3    3     3
                          Therefore, the given box can be completed as shown here:                             2   4
                                                                                                               3   3   2
                                                                                                               1   2   1
                                                                                                               3   3
                                                                                                               1   2
                                                                                                               3   3   1
                                                                 1                                   3                  1
                    Ex 7.  On a given day, a labourer earned `358 . Out of this money, he spent `102  on food and ` 46
                                                                 2                                   4                  5
                          on other needs. How much money was left with him?
                                                            1      3      1   717   411 231
                    Sol.  Money left with the labourer = 358 − 102 −   46 =       −     −
                                                            2      4      5    2     4     5

                                                                                ×
                                                        717 ×10 411    ×− 231 4
                                                                 −
                                                                        5
                                                      =                                            ( LCM (2, 4, 5) = 20)
                                                                    20
                                                        7170 − 2055 924       4191         11
                                                                    −
                                                      =                   = `      = ` 209
                                                                20             20          20
                      Exercise 7.4
                    1.  Evaluate:

                             4   15                 17     2                   1  5                    3    1
                        (a)    +                (b)    + 3               (c)  9 −                 (d)  6 + 3
                            17 17                    2     6                   4  4                    5    3
                              1    1
                        (e)  9 − 5
                              2    6                               3  1        1

                    2.  Write the correct value in the box:  (a)   −=  4  ,  (b)   2  +  =  2
                                                                   8
                    3.  Find the value of:
                              3  4    2              5    7   11               2  1    1                 2   7
                        (a)  2 +   +  1         (b)    −    +            (c)  4 +−    4           (d)  2 −+
                              5  5    5             12 12 12                   3  3     3                3   3
                    4.  Find the value of:
                              2    1    1            5       5               1   7    1                  7     1
                                                        61
                        (a)  4 − 3 +  2         (b)   ++                 (c)   −+   5             (d)  7 +  +  5
                              3    4    6            9       7               7   3    6                  4     6

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