Page 296 - Ganit Kaushal

17. By observation, superimposition, circular aid and by 4. (a) 67,82,601 (b) 8,07,00,079
using a protractor. (c) 5,76,37,604 (d) 91,857,609
18. (a) (i) Lines AC and ED 5. (a) 100 (b) 1000 (c) 100 (d) 10,000
(ii) Lines AC, AD; Lines AC, CD; Lines AD, ED;
Lines ED, CD; Lines AD, CD. (e) 10.

6. 9994, 9995, 9996, 9997, 9998, 9999, 10000, 10001,

(iii) AD , ED , CD 10002, 10003.
(b) (i) False (ii) False 7. 1980, 1985, 1990, 1995, 2000, 2005, 2010, 2015, 2020,

19. (a) l, m (b) l, n; l, p; m, n; m, p; n, p 2025.
(c) l, p (d) A, B, C; A, E, D 8. 15077, 15078, 15079, 15080, 15081, 15082, 15083,

20. (a) 180° (b) 90° (c) 180° 15084, 15085, 15086.
21. (a) At 10 9. 83705, 84705, 85705, 86705, 87705, 88705, 89705,

(b) At 12, No, (because 2 straight angles bring it back 90705, 91705, 92705.
to original position) 10. The complete table is
(c) At 4
3-digit
2-digit
1-digit
5-digit
4-digit
Assertion Reason Type Questions numbers numbers numbers numbers numbers
1. (c) 2. (a) 3. (a) 4. (b) From: 1-9 10-99 100-999 1000-9999 10,000-99,999
5. (d) 6. (b) 7. (a) 8. (a) 9 90 900 9,000 90,000
Chapter Test
I. 1. (b) 2. (a) 3. (b) 4. (b) (Hint: Total numbers from ‘m’ to ‘n’ is given by the
5. (b) 6. (a) 7. (d) formula (n – m + 1); m < n)

8. (c) (Starting at 0°, each 10 degree apart up to 180°) 11. Yes, there is a pattern. The pattern is 3n; n = 2, 3, 4,
II. 1. Intersecting 2. Parallel 3. Length 4. Protractor 5, 6, 7, 8, i.e., The pattern is thrice of middle digit.
5. Twice 6. Breadth (Hint: Observe that Sum of 123 = 6 = 3 × 2; Sum of
III. 1. True 234 = 9 = 3 × 3; Sum of 345 = 12 = 3 × 4 …)
2. False ( It leads to 3 divisions of a region, namely, 12. 59

interior, exterior and the boundary) 13. 95000 (Hint: To find the greatest number, digits are
3. False ( Three right angles are equal to 270 degrees) put in decreasing order)

4. True 5. True 6. True 14. Can’t be told as we can put as many zeros after 95 as
IV. 1. By observation, by superimposition, by circular aids, we wish and the sum of digits will always remain 14;
by measuring with protractor. Yes, by putting one more zero after 95 and this process
will never end.
2. Explain in your own words.

3. No, More than one angle is possible at the point P. 15. 20 – times. (Hint: 7 at one’s place: 07, 17, 27, … 97.
– 10 times, 7 at tens place: 70, 71, 72, …, 79. Again
10 times. So total 10 + 10 = 20 times)
Chapter 3: Number Play
16. 300 – times. (Hint: Similar as above: 7 at one’s place:

Exercise 3.1 007 to 997 – 100 times, 7 at ten’s place: 070 to 979 –
1. (a) 23578, 87532 (b) 30469, 96430 again 100 times, 7 at hundredth place: 700 to 799 –
(c) 20378, 87320 again 100 times, So, total 100 + 100 + 100 = 300
2. 86230, 30268 times.)
3. (a) 12,45,678; Twelve lakh forty-five thousand six 17. (a) quotient-67, remainder-8; 879 = 13 × 67 + 8.
hundred seventy-eight. (b) quotient-455, remainder-15; 7750 = 17 × 455 + 15.
(b) 63,54,793; Sixty-three lakh fifty-four thousand 18. 707 (Hint: 33×21+14) 19. 20 20. 10160
seven hundred ninety-three. 21. 987 22. 7
(c) 7,77,00,087; Seven crore seventy-seven lakh eighty-
seven. Exercise 3.2

(d) 9,65,37,801; Nine crore sixty-five lakh thirty-seven 1. One of the possible ways to get maximum number of
thousand eight hundred one. super cells is given below. There can be many more.
(e) 5,84,26,973; Five crore eighty-four lakh twenty-six Students are advised to explore other options also.
thousand nine hundred seventy-three. 999 100 150 105 202 165 888 808 998

294 Mathematics-6