Page 129 - Information_Practice_Fliipbook_Class11
P. 129
Assuming ShtlvnautloflShtlvnrinbatlnum Solbtl10linlShtlcodtlnbovtlntlwtaalntlinltnchloflShtlfoaaowinglcodtltnipptStlI,lII,l
nndlIII,ldtStreintlwhichloflShtlcodtltnipptStlwiaalproductlShtltnetlouSpuSlonltxtcuSionlntlShtlnbovtlcodtlwiaalproductl
onliStltxtcuSion?
I.
if num < 0:
print(num, " is a negative number")
elif num > 0:
print(num, " is a positive number")
else:
print(num, " is zero")
II.
if num < 0:
print(num, " is a negative number")
if num > 0:
print(num, " is a positive number")
else:
print(num, " is zero")
III.
if num < 0:
print(num, " is a negative number")
if num > 0:
print(num, " is a positive number")
else:
print(num, " is zero")
n.l IIlonay
b.l IIlnndlIII
c.l Ilonay
d.l I,lII,lnndlIII
9. WhnSlwiaalbtlShtlouSpuSlproductdlonltxtcuSionloflShtlfoaaowinglcodt?
num = 3
if (num > 2):
num = num * 2
if (num > 4):
num = 0
print(num)
n.l 3l b. 0l c. 6l d. Error
10. WhnSlwiaalbtlShtlouSpuSlproductdlonlShtltxtcuSionloflShtlfoaaowinglcodt?
mass = 0.5
itemCount = 10
if mass < 2:
amount = 1.45
if mass >= 2:
amount = 1.2
total = mass * amount
if itemCount > 10:
total = total * 0.7
print(total)
n.l 0.725l b. 0.5075l c. 0.6l d. 0.42l
Conditonnal SnStetnSt 115

