Page 119 - Information_Practice_Fliipbook_Class11
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06 else:
07 print("Number is ODD")
08 print("Divisibility Check Done")
InlShtlnbovtltxnepat,liflnum itltvtn,lShtlconditonnaltxprtttionlinlShtlifltSnStetnSlyitadtlTrue, nndlShtltSnStetnStl
inlShtliflbaocklnrtltxtcuStd.lHowtvtr,liflShtlconditonnaltxprtttionlyitadtlFalse,lShtltSnStetnS,l
print("Number is ODD")
itltxtcuStd.lThtltSnStetnS,l
print("Divisibility Check Done")
itltxtcuStdlinlboShlcnttt.lForltxnepat,ltuppottlShtluttrltnStrtlShtlinpuS 24lwhtnlShtlnbovtlcodtlitltxtcuStd.l o,lShtl
conditonnaltxprtttionl24%2 == 0l(orltquivnatnSayl0 == 0)lyitadt True,l o,lShtlSwoltSnStetnStlinlShtliflbaockl
wiaalgtSltxtcuStd.lConttqutnSay,lShtlPyShonlinStrprtStrlwiaalproductlShtlfoaaowinglouSpuS:
>>> Enter a number: 24
Number is EVEN
Division by 2 leaves the remainder Zero
Divisibility Check Done
NtxS,ltuppottlShtluttrltnStrtlShtlinpuS 15lwhtnlShtlnbovtlcodtlitltxtcuStd.lThtlPyShonlinStrprtStrlwiaalproductl
ShtlfoaaowinglouSpuS:l
>>> Enter a number: 15
Number is ODD
Divisibility Check Done
Program 5.2 WriStlnlprogrnelShnSlncctpStlnlnuebtrlfroelnluttrlnndlouSpuStlnletttngtlindicntnglwhtShtrliSlitlnn
tvtnleuatpat oflfivt.lISlenylbtltntitrlSolwriStlShtlcodtliflyoulrtcnaalShnSlPyShonlinStrprtStl0lntlFalse.
Solution:
01 # Objective: To check whether a number is even multiple of 5
02 number = int(input("Enter a number: "))
03 if number%2 == 0 and number%5 == 0:
04 print("Even Multiple of 5")
05 else:
06 print("NOT Even Multiple of 5")
nepatlouSpuSl1:
>>> Enter a number: 10
Even Multiple of 5
nepatlouSpuSl2:
>>> Enter a number: 12
NOT Even Multiple of 5
TolcoebintlSwolorleortlconditont,lwtlenyluttlaogicnaloptrnSort.lForltxnepat:
if num > 0 and num%2 == 0:
print("Positive Even Number")
IflShtlvnautloflnum itlgrtnStrlShnnl0lnndliflnum itldivitibatlbyl2,lShtlconditonnaltxprtttionlwiaaltvnaunStlSolTrue.lOnayl
Shtn,lShtltSnStetnS,lprint("Positive Even Number")wiaalbtltxtcuStd.
Program 5.3 WriStl nl progrnel ShnSl coepuSttl nl tSudtnS'tl rttuaSl bnttdl onl hitl ptrctnSngtl ofl enrkt.l Contidtringl
passPercent So btl33,liflShtltSudtnSlhntltcortdl33lorleortlShnnl33lptrctnS,lShtlconditonnaltxprtttionlpercent
>= passPercent wiaal yitadl True,l nndl Shtl tSnStetnSl inl Shtl ifl baockl wiaal gtSl txtcuStd.l Thut,l Shtl progrnel
wiaalprinS "Passed".lOnlShtlconSrnry,liflShtltSudtnSlhntltcortdlatttlShnnl33lptrctnS,lShtlconditonnaltxprtttionl
percent >= passPercent wiaalyitad False,lnndlShtltSnStetnSlinlShtlelselbaocklwiaalbtltxtcuStd.l o,lShtl
progrne will prinSl"Failed".
Solution:
01 '''
02 Objective: To compute a student's result
Conditonnal SnStetnSt 105

