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06 else:
              07     print("Number is ODD")
              08 print("Divisibility Check Done")
            InlShtlnbovtltxnepat,liflnum itltvtn,lShtlconditonnaltxprtttionlinlShtlifltSnStetnSlyitadtlTrue, nndlShtltSnStetnStl
            inlShtliflbaocklnrtltxtcuStd.lHowtvtr,liflShtlconditonnaltxprtttionlyitadtlFalse,lShtltSnStetnS,l
                print("Number is ODD")
            itltxtcuStd.lThtltSnStetnS,l

                print("Divisibility Check Done")
            itltxtcuStdlinlboShlcnttt.lForltxnepat,ltuppottlShtluttrltnStrtlShtlinpuS 24lwhtnlShtlnbovtlcodtlitltxtcuStd.l o,lShtl
            conditonnaltxprtttionl24%2 == 0l(orltquivnatnSayl0 == 0)lyitadt True,l o,lShtlSwoltSnStetnStlinlShtliflbaockl
            wiaalgtSltxtcuStd.lConttqutnSay,lShtlPyShonlinStrprtStrlwiaalproductlShtlfoaaowinglouSpuS:

             >>> Enter a number: 24
                 Number is EVEN
                 Division by 2 leaves the remainder Zero
                 Divisibility Check Done
            NtxS,ltuppottlShtluttrltnStrtlShtlinpuS 15lwhtnlShtlnbovtlcodtlitltxtcuStd.lThtlPyShonlinStrprtStrlwiaalproductl
            ShtlfoaaowinglouSpuS:l

             >>> Enter a number: 15
                 Number is ODD
                 Divisibility Check Done
            Program 5.2 WriStlnlprogrnelShnSlncctpStlnlnuebtrlfroelnluttrlnndlouSpuStlnletttngtlindicntnglwhtShtrliSlitlnn
            tvtnleuatpat oflfivt.lISlenylbtltntitrlSolwriStlShtlcodtliflyoulrtcnaalShnSlPyShonlinStrprtStl0lntlFalse.
            Solution:
              01 # Objective: To check whether a number is even multiple of 5
              02 number = int(input("Enter a number: "))
              03 if number%2 == 0 and number%5 == 0:
              04     print("Even Multiple of 5")
              05 else:
              06     print("NOT Even Multiple of 5")
             nepatlouSpuSl1:

             >>> Enter a number: 10
                 Even Multiple of 5
             nepatlouSpuSl2:

             >>> Enter a number: 12
                 NOT Even Multiple of 5
            TolcoebintlSwolorleortlconditont,lwtlenyluttlaogicnaloptrnSort.lForltxnepat:
                 if num > 0 and num%2 == 0:
                     print("Positive Even Number")
            IflShtlvnautloflnum itlgrtnStrlShnnl0lnndliflnum itldivitibatlbyl2,lShtlconditonnaltxprtttionlwiaaltvnaunStlSolTrue.lOnayl
            Shtn,lShtltSnStetnS,lprint("Positive Even Number")wiaalbtltxtcuStd.

            Program  5.3  WriStl nl progrnel ShnSl coepuSttl nl tSudtnS'tl rttuaSl bnttdl onl hitl ptrctnSngtl ofl enrkt.l Contidtringl
            passPercent So btl33,liflShtltSudtnSlhntltcortdl33lorleortlShnnl33lptrctnS,lShtlconditonnaltxprtttionlpercent
            >=  passPercent  wiaal yitadl True,l nndl Shtl tSnStetnSl inl Shtl ifl baockl wiaal gtSl txtcuStd.l Thut,l Shtl progrnel
            wiaalprinS "Passed".lOnlShtlconSrnry,liflShtltSudtnSlhntltcortdlatttlShnnl33lptrctnS,lShtlconditonnaltxprtttionl
            percent >= passPercent wiaalyitad False,lnndlShtltSnStetnSlinlShtlelselbaocklwiaalbtltxtcuStd.l o,lShtl
            progrne will prinSl"Failed".

            Solution:
              01 '''
              02 Objective: To compute a student's result

                                                                                          Conditonnal SnStetnSt  105
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