Page 167 - Math Genius C3
P. 167

E:\Working\Orange_Education\Math_Genius_3_(08-10-2025)\Open_Files\CHAP_09
               \ 08-Oct-2025  Bharat Arora   Proof-10                                       Reader’s Sign _______________________ Date __________





              Example 3: Subtract 18 kg 628 g from 29 kg 76 g.
 Think Tank  Logical Thinking
              Solution:    Arrange the given measures in the kg and g columns such that the smaller
 Sania’s  family  wants  to  go  to  the  shopping  mall
 by the shortest route. The picture shows the   weight is written below the bigger weight. Then subtract them.
 distance between the places using two different   Step 1: Subtract ‘g’.
 routes.
                                       We cannot subtract 628 g from 76 g as 76 < 628.
  1.   Which  route  should  they  take:  home  to
 shopping  mall  via  the  temple  or  home  to               So, we borrow 1 kg from 29 kg, leaving behind 28 kg.
 shopping mall via the bank?              Now 1 kg 76 g = 1076 g

      ______________________              And 1076 g – 628 g = 448 g                                  kg        g
  2.   How much more distance will they cover if
 they take the longer route?              Write 448 under the g column.                                 8 10 6 16
       ______________________  Step 2: Subtract ‘kg’.                                                2 9 0 7 6

                                       28 kg – 18 kg = 10 kg                                     – 1 8 6 2 8
                                                                                                     1 0 4 4 8
 Subtraction of WeightS                Write 10 under the kg column.
                             Thus, 29 kg 76 g – 18 kg 628 g = 10 kg 448 g
 Example 1: Subtract:

 (a)  350 g from 900 g       (b)  17 kg from 30 kg  Subtraction of capacitieS

 Solution:  (a)  8 10  (b)  2 10  Example 1: Subtract the following:
                   (a)  550 mL – 275 mL                              (b)  248 L – 198 L
 9 0 0 g  3 0 kg
 – 3 5 0 g  – 1 7 kg  Solution:  (a)     14                          (b)      1 14

 5 5 0 g  1 3 kg                      4   4 10                                2 4 8 L
                                      5 5 0 mL                             – 1 9 8 L
 Example 2: Subtract 14 kg 569 g from 21 kg 664 g.  – 2 7 5 mL                    5 0 L


 Solution:   Write  the given measures in the kg and g columns such that the smaller   2 7 5 mL
 weight is written below the bigger weight. Then subtract them.  Example 2: Subtract 15 L 346 mL from 20 L 940 mL.


 Step 1: Subtract grams (g).  kg  g  Solution:  Arrange the given measures in the L and mL columns and then subtract.

             664 g – 569 g = 95 g  15  Step 1: Subtract the millilitres.                               L       mL
 1 11 5  5 14
             Write 95 under the g column.  2 1 6 6 4              940 mL – 346 mL = 594 mL           1 10 8    13
                                                                                                                3 10
 Step 2: Subtract kilograms (kg).  – 1 4 5 6 9              Write 594 under the ml column.           2 0 9 4 0
 7 0 9 5                     Step 2: Subtract the litres.
             21 kg – 14 kg = 7 kg                                                                – 1 5 3 4 6
                                       20 L – 15 L = 5 L                                                5 5 9 4
             Write 7 under the kg column.
                                       Write 5 under the L column.
       Thus, 21 kg 664 g – 14 kg 569 g = 7 kg 95 g        Thus, 20 L 940 mL – 15 L 346 mL = 5 L 594 mL.





              Mathematics-3                                                                                         165
   162   163   164   165   166   167   168   169   170   171   172