Page 102 - Math Genius C4
P. 102
E:\Working\Orange_Education\Math_Genius_4\Open_Files\Chap-05
\ 30-Sep-2025 Bharat Arora Proof-9 Reader’s Sign _______________________ Date __________
Factor tree Method
In this method, we write pairs of factors for the given number in circles which make
branches of a factor tree.
Example 2: Find the prime factorisation of 48 by using the factor tree method.
Solution: We can prime factorise the number 48 by the factor tree method as
explained below. 48
Step 1: Start with any comfortable pair of factors 4 × 12
called a factor pair. Here, 4 × 12 = 48
2 × 2 4 × 3
Step 2: If the number at the end of a branch is prime,
2 × 2
we circle it and stop working at that branch. 48 = 2 × 2 × 2 × 2 × 3
Step 3: If the number at the end of the branch is
composite, we continue till the end of each branch is a prime
number and circled.
Step 4: The product of all the circled numbers is the required prime
factorisation of the given number.
Be Aware
In a factor tree, we can use a box to represent a composite number.
Different factor trees can be made for a given number.
Alternatively,
Step 1: Find two factors such that one is the smallest prime number.
Step 2: Circle the smallest prime factor and work on the 48
other factor (branch) if it is not prime (composite).
2 × 24
Step 3: Continue the process till the number at the end of
2 × 12
each branch is circled.
2 × 6
Step 4: The product of all the circled factors is the required
prime factorisation of the given number. 2 × 3
Division Method
Divide the given numbers by the smallest prime number. Continue the division until
it is not further divisible. Division stops when we reach a prime number.
100 Mathematics-4

