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               \ 30-Sep-2025  Bharat Arora   Proof-9                                Reader’s Sign _______________________ Date __________






                       Practice time 4e

                1.  Match the division problems with their estimated quotients correctly.

                          Column A                                                Column B
                    (a) 93 ÷ 27                                              (i)  5

                    (b) 903 ÷ 62                                             (ii) 3
                    (c) 573 ÷ 61                                             (iii) 10
                    (d) 305 ÷ 63                                             (iv) 15

                2.  Find the estimated quotients by rounding off the numbers to their highest place.

                    (a)  88 ÷ 34            (b)  257 ÷ 28            (c)  481 ÷ 14           (d)  395 ÷ 16

                    (e)  2402 ÷ 44           (f)  3821 ÷ 22          (g)  4620 ÷ 48          (h)  7004 ÷ 53


              WorD Problems


              Example 1:  A  wholesaler  has  11232  kg of wheat contained  in  24                  24   11232 468
              sacks equally. Find the weight of wheat in each sack.                                    –   96

              Solution:  Total quantity of wheat = 11232 kg                                            –   163
                                                                                                           144
                             Number of sacks = 24                                                           192
                             Quantity of wheat in each sack = 11232 ÷ 24 = 468 kg                      –    192
                                                                                                               0
                             Thus, the weight of wheat in each sack is 468 kg.

              Example 2:  There is an equal number of students in each of the 8 houses of a school.
              If there are 488 students in the school, how many students are there in each house?

              Solution:  Number of houses = 8                                                             8  488 61

                             Total number of students = 488                                                –  48
                             Number of students in each house = 488 ÷ 8 = 61                                     8

                             Thus, the number of students in each house is 61.                             –     8
                                                                                                                 0
              the four oPerations together


              The fundamental operations in mathematics are addition, subtraction, multiplication
              and  division.  Now, we will  learn  to solve mixed operation  problems,  which  require
              more than one operation to get the solution.

              To solve a mixed operation problem, keep the following things in mind.
                     Š Read the problem carefully and visualise it in your mind.

                     Š Identify the keywords in the problem and mark them.
                     Š Find the operations needed to solve the problem.


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