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               \ 08-Oct-2025  Bharat Arora   Proof-9                                 Reader’s Sign _______________________ Date __________





 Example 5:  Find the area of a square whose length is 14 cm.  14 cm  Example 2:  Find the area of the following figure.
 Solution:   Length of a side of the square = 14 cm                          8 cm

          Area of the square =  side × side  14 cm      6 cm
             =  14 cm × 14 cm = 196 sq. cm      10 cm         12 cm                  8 cm
 Example 6:  Find the area of a square whose perimeter is 84 cm.
 Solution:   Perimeter of the square  = 84 cm                   24 cm

          Side of the square =  Perimeter of the square ÷ number of sides   Solution:     We divide the given figure into rectangles and a square.
                        = (84 ÷ 4) cm = 21 cm           Area of rectangle A = 10 cm × 4 cm = 40 sq. cm

          Now, area of the square = side × side           Area of rectangle B = 12 cm × 4 cm  4 cm
             = (21 × 21) sq. cm = 441 sq. cm        = 48 sq. cm                         6 cm                  8 cm
          Thus, the area of the square is 441 sq. cm.     Area of square C = 8 cm × 8 cm  10 cm  A  12 cm            8 cm
                                                    = 64 sq. cm                         4 cm   B               C

 Think Tank  Critical Thinking           Thus, the area of the given shape                      24 cm
 What will be the length of the side of a square whose area and perimeter are equal?              = Area of square C + Area of rectangle B + Area of rectangle A

                                 = (64 + 48 + 40) sq. cm = 152 sq. cm.
 FACTS
 Two rectangles can have the same perimeter but very different areas. A long, skinny rectangle    AreA of A triAngle
 such as 1 cm by 9 cm has a perimeter of 20 cm and an area of 9 sq. cm. On the other hand, a square-  Look at the square shown alongside.
 like rectangle such as 5 cm by 5 cm also has a perimeter of 20 cm, but its area is much larger, i.e.,
 25 sq. cm.   Area of the square = 6 cm × 6 cm = 36 sq. cm
              A diagonal divides a square into two halves. Each half is a triangle.
 AreA of A CompoSite figUre  Thus, the area of a triangle is half the area of the square.                           6 cm

 Example 1:  Find the area of the following figure.     Area of each triangle =  Area of the square

 5 cm                                                          2                                         6 cm
                                                     36
                                                   =      sq. cm = 18 sq. cm.
                                                      2
 1 cm
 3 cm
 1 cm         Is this also true for a rectangle? Let us see.
              Here, a rectangle whose length is 8 cm and breadth is 6 cm is                                         6 cm
              given.

 5 cm         Area of the rectangle = 8 cm × 6 cm = 48 sq. cm                                         8 cm
 Solution:     The  given  figure  can  be  divided  into  three  rectangles  as   (I)  1 cm
 shown.       Again, the diagonal divides the rectangle into two equal halves, and each half is a triangle.

          Area of rectangle (I) = 5 cm × 1 cm = 5 sq. cm  1 cm  3 cm  So, area of each triangle = 48 ÷ 2 sq. cm = 24 sq. cm.

          Area of rectangle (II) = 3 cm × 1 cm = 3 sq. cm  (II)  Now, let us find the area of the triangles shown below.
          Area of rectangle (III) = 5 cm × 1 cm = 5 sq. cm     (  a)      (  b)
 (III)
          Area of the complete figure

                = area of rectangle (I) + area of rectangle (II) + area of rectangle (III)
                = 5 sq. cm + 3 sq. cm + 5 sq. cm = 13 sq. cm


              Mathematics-5                                                                                         207207
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