Page 46 - Math Genius C5

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\\October 8, 2025 12:09 PM Bharat Arora P-9 Reader _________________________ Date: ___________________74

( b) 1 1 6 8 Q Step 1: Divide 303 by 260. Properties of division
260 3 0 3 6 8 3 260 × 1 = 260 is the maximum possible product 1. When a number is divided by itself, the quotient is 1.
– 2 6 0 < 303. examples: (a) 36 ÷ 36 = 1 (b) 239 ÷ 239 = 1

4 3 6 Subtract 260 from 303 and bring down 6. 2. When a number is divided by 1, the quotient is the number itself.
– 2 6 0 Step 2: 436 is the new partial dividend. Here, 260 × 1 = 260 examples: (a) 37 ÷ 1 = 37 (b) 325 ÷ 1 = 325

1 7 6 8 is the maximum possible product < 436. 3. When 0 is divided by a non-zero number, the quotient is zero.
– 1 5 6 0 Subtract 260 from 436 and bring down 8. examples: (a) 0 ÷ 44 = 0 (b) 0 ÷ 365 = 0

2 0 8 3 Step 3: 1768 is the new partial dividend. Here, 260 × 6
– 2 0 8 0 = 1560 is the maximum possible product < 1768. 4. Division by 0 is meaningless.

3 R Subtract 1560 from 1768 and bring down 3. Critical Thinking

Step 4: Now, 2083 is the new partial dividend. Here, Think Tank
260 × 8 = 2080 is the maximum possible product Vanraj bought an inverter battery. He read on it: Life—8760 hours. He uses it
throughout the day and the night. How many days will the battery run?
< 2083. Subtract 2080 from 2083.
Step 5: 3 is left which is less than 260 and nothing is left
to bring down. Practice time 2d
Thus, Quotient = 1168 and Remainder = 3. 1. Find the quotient and remainder and check your answer.
Checking:
Quotient × Divisor + Remainder = Dividend Think Tank ( a) 2,75,736 ÷ 9 (b) 8,76,048 ÷ 7 (c) 6,83,396 ÷ 15 (d) 4,36,263 ÷ 23
1168 × 260 + 3 = 3,03,683 I am a 3-digit number. ( e) 8,04,009 ÷ 78 (f) 1,83,648 ÷ 143 (g) 7,28,804 ÷ 192 (h) 3,55,444 ÷ 222

3,03,680 + 3 = 3,03,683 If you multiply me by 2, you get 420. 2. Find the dividend, if
3,03,683 = 3,03,683 What number am I? ( a) divisor = 136, quotient = 75 and remainder = 31.
Hence, the division is correct.
example 4: Delhi Jal Board supplied 9,78,795 litres of water in a colony which had 375 ( b) divisor = 403, quotient = 801 and remainder = 325.

families. How much water did each family get if each family got the same amount of water 3. Fill in the blanks.
and how much water was left? ( a) 789 ÷ 789 = ______ (b) 5342 ÷ ______ = 5342 (c) ______ ÷ 6574 = 1
Solution: Total quantity of water supplied = 9,78,795 litres 2 6 1 0 Q ( d) ______ ÷ 218 = 0 (e) If 4032 ÷ 24 = 168, then 24 × 168 = ______

9 7 8 7 9 5
Total number of families = 375 375 7 5 0 4. Match the following columns:
Quantity of water each family got = (9,78,795 ÷ 375) litres 2 2 8 7 Column-I Column-II

Thus, each family of the colony got 2610 litres of water 2 2 5 0 (a) 54,363 ÷ 10 (i) Q = 430, R = 33
and 45 litres of water was left. 3 7 9 (b) 43,033 ÷ 100 (ii) Q = 487, R = 6
3 7 5
4 5 R (c) 9,21,735 ÷ 1000 (iii) Q = 5436, R = 3
(d) 55,569 ÷ 100 (iv) Q = 697, R = 770
example 5: The cost of 125 radio sets is `1,04,500. What is the cost of one radio?
(e) 4876 ÷ 10 (v) Q = 921, R = 735
Solution: Cost of 125 radio sets = `1,04,500 8 3 6 Q (f) 6,97,770 ÷ 1000 (vi) Q = 555, R = 69
1 0 4 5 0 0
Cost of 1 radio set = `1,04,500 ÷ 125 = `836 125 1 0 0 0
Thus, the cost of one radio set is `836. 4 5 0 5. Solve the following word problems.
– 3 7 5 ( a) The cost of 130 radio sets is `2,99,520. What is the cost of one radio set?
7 5 0 ( b) The product of two numbers is 3,32,878. If one of the numbers is 826, find the
– 7 5 0
0 0 0 R other number.

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