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               \ 08-Oct-2025  Bharat Arora   Proof-9                                 Reader’s Sign _______________________ Date __________





                                                                  12
              Example 2:  Find two equivalent fractions of            .
                                                                  18             Think Tank                    Logical Thinking

              Solution:     We have:    12  =   12 ÷ 2  =   6                  I am  a  proper  fraction. The
                                                                               sum of my numerator and denominator
                                        18     18 ÷ 2     9                    is 15. The  product of my  numerator

                            and         12  =  12 ÷ 3   =  4                   and denominator is 54. What fraction
                                                                               am I? Now, find two fractions that are
                                        18     18 ÷ 3     6                    equivalent to me.
                                     6       4                                 12
                            Hence,  and   are equivalent fractions of             .
                                     9       6                                 18

              rEducing a Fraction to its lowEst tErMs

              A  fraction  is  said  to  be  in  its  lowest  term  (or  simplest  form),  if  the  numerator  and  the
              denominator of the fraction have no common factor except 1.
              To reduce a fraction to its lowest term, the numerator and the denominator of the fraction
              are divided by their HCF.

              Example:      Reduce the following fractions to their simplest form.
                    (  a)   108                                      (b)   135
                        126                                              300
              Solution:     (a)  First, we find the HCF of the numerator 108 and the denominator 126.

                                   2 108        2 126
                                   2 54         3 63
                                   3 27         3 21
                                   3   9        7    7
                                   3   3             1
                                       1

                                 Clearly, 108 = 2 × 2 × 3 × 3 × 3 and 126 = 2 × 3 × 3 × 7.
                                 Therefore, HCF of 108 and 126 = 2 × 3 × 3 = 18.
                                        108      108 ÷ 18      6
                                 N  o  w  ,      =           =
                                        126      126 ÷ 18      7

                                 Thus,   6   is the simplest form of   108 .
                                         7                             126
                            (  b)  First, we find the HCF of the numerator 135 and the denominator 300.
                                   3 135         2 300
                                   3 45          2 150
                                   3 15          3 75                            Think Tank                    Logical Thinking
                                   5   5         5 25                          Is every unit fraction in its
                                       1         5    5                        simplest form?
                                                      1
                                 Clearly, 135 = 3 × 3 × 3 × 5 and 300 = 2 × 2 × 3 × 5 × 5.
                                 Therefore, HCF of 135 and 300 = 3 × 5 = 15.

                                 N  o  w  ,     135  =   135 ÷ 15  =   9
                                        300      300 ÷ 15       20
                                          9                              135
                                 Thus,       is the simplest form of          .
                                         20                              300

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