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               \ 08-Oct-2025  Bharat Arora   Proof-9                                 Reader’s Sign _______________________ Date __________





                                                                                        5 7 1 2
              Example 4:  Arrange the following fractions in ascending order:  ,  ,  ,  .
                                                                                        6 9 2 3
              Solution:     Change  the  given  fractions  into  their  respective  equivalent  fractions  having
                            the  same  denominator  equal  to  the  LCM  of  the  denominators  of  the  given
                            fractions. The LCM of the denominators 6, 9, 2 and 3 is 18.
                                    5
                            Then,  =     5 × 3  =   15 7    7 × 2  =   14
                                                      ;   =
                                    6    6 × 3    18 9      9 × 2     18                             2 6, 9, 2, 3
                                                        2
                                    1  =   1 × 9  =   9  ;   =  2 × 6  =   12                        3 3, 9, 1, 3
                                    2    2 × 9     18 3      3 × 6    18                             3 1, 3, 1, 1
                            9 < 12 < 14 < 15                                                            1, 1, 1, 1

                            Therefore,    9   <   12  <   14  <   15                           LCM = 2 × 3 × 3 = 18
                                         18     18     18    18
                                        2
                                   1
                                             7
                                                  5
                            Thus,  <   <   <  .
                                   2    3    9    6
              Example 5:  Arrange the following fractions in descending order:             3 5 2 1
                                                                                             ,  ,  ,  .
                                                                                          10 8 5 3
              Solution:     Change  the  given  fractions  into  their  respective  equivalent  fractions  having
                            the  same  denominator  equal  to  the  LCM  of  the  denominators  of  the  given
                            fractions. The LCM of the denominators 10, 8, 5 and 3 is 120.

                            Then,    3   =   3 × 12   =   36 5    5 × 15   =   75
                                                           ;   =
                                    10    10 × 12      120 8      8 × 15     120              2 10, 8, 5, 3
                                    2  =   2 × 24  =   48 1    1 × 40   =   40                2 5, 4, 5, 3
                                                        ;   =
                                    5    5 × 24     120 3      3 × 40     120                 5 5, 2, 5, 3
                            75 > 48 > 40 > 36                                                     1, 2, 1, 3
                                          75      48      40     36
                            Therefore,         >      >       >
                                         120     120     120     120                LCM = 2 × 2 × 2 × 3 × 5 = 120
                                               1
                                         2
                            Thus,  5   >   >   >     3  .
                                   8     5     3    10
              Method of cross-Multiplication


              We can also compare two fractions by the cross-multiplication method.
              In this method, the numerator of the first fraction is multiplied by the denominator of the
              second fraction and the numerator of the second fraction is multiplied by the denominator
              of the first fraction.
                                                                                          8
                                             8
              Example: Let us compare   and          5  . Cross-multiply the fractions   and       5  .
                                             9       11                                   9       11
                          8       5       9 × 5 = 45
                           9     11       8 × 11 = 88

              The cross-products are 88 and 45.                             The first product is greater than
                                                                                 the second product.
              Clearly, 88 > 45.                                            So, the first fraction > the second
                                                                                      fraction.
                   8
              So,   >    5
                   9     11

              Mathematics-5                                                                                          87
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