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\ 08-Oct-2025 Bharat Arora Proof-9 Reader’s Sign _______________________ Date __________
5 7 1 2
Example 4: Arrange the following fractions in ascending order: , , , .
6 9 2 3
Solution: Change the given fractions into their respective equivalent fractions having
the same denominator equal to the LCM of the denominators of the given
fractions. The LCM of the denominators 6, 9, 2 and 3 is 18.
5
Then, = 5 × 3 = 15 7 7 × 2 = 14
; =
6 6 × 3 18 9 9 × 2 18 2 6, 9, 2, 3
2
1 = 1 × 9 = 9 ; = 2 × 6 = 12 3 3, 9, 1, 3
2 2 × 9 18 3 3 × 6 18 3 1, 3, 1, 1
9 < 12 < 14 < 15 1, 1, 1, 1
Therefore, 9 < 12 < 14 < 15 LCM = 2 × 3 × 3 = 18
18 18 18 18
2
1
7
5
Thus, < < < .
2 3 9 6
Example 5: Arrange the following fractions in descending order: 3 5 2 1
, , , .
10 8 5 3
Solution: Change the given fractions into their respective equivalent fractions having
the same denominator equal to the LCM of the denominators of the given
fractions. The LCM of the denominators 10, 8, 5 and 3 is 120.
Then, 3 = 3 × 12 = 36 5 5 × 15 = 75
; =
10 10 × 12 120 8 8 × 15 120 2 10, 8, 5, 3
2 = 2 × 24 = 48 1 1 × 40 = 40 2 5, 4, 5, 3
; =
5 5 × 24 120 3 3 × 40 120 5 5, 2, 5, 3
75 > 48 > 40 > 36 1, 2, 1, 3
75 48 40 36
Therefore, > > >
120 120 120 120 LCM = 2 × 2 × 2 × 3 × 5 = 120
1
2
Thus, 5 > > > 3 .
8 5 3 10
Method of cross-Multiplication
We can also compare two fractions by the cross-multiplication method.
In this method, the numerator of the first fraction is multiplied by the denominator of the
second fraction and the numerator of the second fraction is multiplied by the denominator
of the first fraction.
8
8
Example: Let us compare and 5 . Cross-multiply the fractions and 5 .
9 11 9 11
8 5 9 × 5 = 45
9 11 8 × 11 = 88
The cross-products are 88 and 45. The first product is greater than
the second product.
Clearly, 88 > 45. So, the first fraction > the second
fraction.
8
So, > 5
9 11
Mathematics-5 87

