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    E:\Working\Brother_Education\Preparatory_Stage_Maths-3_(11-09-2024)\Open_Files\CHAP_09
                 \ 11-Sep-2024                      Sonia Suyal   Proof-1                     Reader’s Sign _______________________ Date __________

                  Example 3: Subtract 18 kg 628 g from 29 kg 76 g.

                  Solution:    Arrange the given measures in the two columns of ‘kg’ and ‘g’ correctly. Now,
                                 subtract them as ordinary numbers.

                                 Step 1: Subtract ‘g’.

                                           We cannot subtract 628 g from 76 g.

                                           So, we borrow 1 kg from 29 kg, leaving behind 28 kg.
                                           Now 1 kg 76 g = 1076 g

                                           And 1076 g – 628 g = 448 g                                   kg          g

                                           Write 448 under the g column.                               1  8     10 6 16

                                 Step 2: Subtract ‘kg’.                                                2 9      0 7 6

                                           28 kg – 18 kg = 10 kg                                   – 1 8        6 2 8

                                           Write 10 under the kg column.                               1 0      4 4 8
                                 Thus, 29 kg 76 g – 18 kg 628 g = 10 kg 448 g

                  suBtraCtion of CaPaCity

                  Example 1: Subtract the following:
                       (a)  550 mL – 275 mL                              (b)  248 L – 198 L

                  Solution:      (a)         14                          (b)      1 14

                                          4   4 10                                2 4 8 L

                                          5 5 0 mL                             – 1 9 8 L
                                       – 2 7 5 mL                                     5 0 L
                                          2 7 5 mL

                  Example 2: Subtract 15 L 346 mL from 20 L 940 mL.

                  Solution:  Arrange the given measures in the columns of L and mL and then subtract.

                                 Step 1: Subtract millilitres.                                           L         mL

                                           940 mL – 346 mL = 594 mL                                                13

                                           Write 594 under the ml column.                              1 10     8   3 10
                                                                                                       2 0
                                 Step 2: Subtract litres.                                           – 1 5       9 4 0
                                                                                                                3 4 6
                                           20 L – 15 L = 5 L                                               5    5 9 4
                                           Write 5 under the L column.

                                 Thus, 20 L 940 mL – 15 L 346 mL = 5 L 594 mL.

                  Mathematics-3                                                                                         159

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