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    E:\Working\Brother_Education\Preparatory_Stage_Maths-3_(11-09-2024)\Open_Files\CHAP_01
                 \ 11-Sep-2024  Sonia Suyal   Proof-1                                         Reader’s Sign _______________________ Date __________

                           Practice time 1D

                  1.  Form the number with:

                       (a)  4 in the thousands place                     (b)  9 in the thousands place
                            8 in the hundreds place                           1 in the hundreds place

                            5 in the tens place                               0 in the tens place
                            2 in the ones place                               6 in the ones place

                  2.  Form the greatest and the smallest 4-digit numbers using the given digits.

                                    digits             greatest 4-digit number             Smallest 4-digit number
                        (a)       3, 7, 1, 9

                        (b)       9, 8, 4, 2
                        (c)       5, 7, 1, 0

                        (d)       4, 7, 9, 7
                        (e)       0, 3, 6, 2

                  3.   Form the greatest and the smallest 4-digit numbers using the given digits with

                       repetition.

                                    digits             greatest 4-digit number             Smallest 4-digit number
                        (a)         1, 4, 7

                        (b)         2, 5, 3
                        (c)         6, 0, 1

                        (d)          2, 3
                        (e)          9, 0

                  suCCessor aND PreDeCessor

                  successor

                  The number that comes just after the given number is called its successor.

                  To find the successor of any number, add 1 to the number.

                  example 1: Find the successor of:
                       (a)  86                          (b)  709                         (c)  2,154

                  Solution:  (a) The successor of 86 is 86 + 1 = 87
                                 (b) The successor of 709  is 709 + 1 = 710

                                 (c) The successor of 2,154 is 2,154 + 1 = 2,155

                  Mathematics-3                                                                                          21

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