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E:\Working\Brother_Education\Preparatory_Stage_Maths-4\Open_Files\Chap-06
\\October 31, 2023 3:34 PM Bharat Arora P-2 Reader _________________________ Date: ___________________74

example 1: Add the following.
(a) 3 and 2 (b) 3 + 2 + 1
7 7 4 4 4
Solution:

+
3 2 32 5
(a) + = = + =
7 7 7 7 3 2 5
7 7 7
(b) 3 + 2 + 1 + +

4 4 4 3 2 1 Remember
++
32 1 4 4 4
= Sum of two or more
4 2 1 like fractions
6 2 1 = + = 1 4 = 1 2 = Sum of numerators
= = 1 = 1 1 2 Common denominator
4 4 2 4 4
subtraction of like Fractions 5

Have a look at the given figure. = 3
4
1
So, – = 4 – 1 = 3 1 5
5
5
5
5
5
We observe that the resultant fraction has the difference of numerators of the given
fractions and same denominator. Remember
Thus, to subtract like fractions, follow these steps: Difference of two like fractions =
Step 1: Subtract the numerators. Difference of numerators

Step 2: Keep the denominator same. Common denominator
Step 3: Reduce the fraction to its simplest form. 9
9 3 10
example 2: Subtract: −
10 10

−
9 3 93 6 3
Solution: − = = =
10 10 10 10 5
6 3
10 10
Practice time 6H

1. Find the sum and express the answer in the simplest form.
9 8 5 8 5 7 4 5 2
(a) + (b) + (c) + (d) + +
4 4 9 9 12 12 7 7 7

2. Subtract the following. reduce the difference to the simplest form.
10 7 9 9 5 3 9 7
(a) − (b) − (c) − (d) −
11 11 13 13 16 16 17 17

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