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D:\Surender Prajapati\Books Final_CBSE and ICSE\ICSE\Preparatory_Stage_Maths-5_(31-10-2023)\Open_Files\CHAP_10
\\November 3, 2023 12:46 PM Surender Prajapati Proof 5 Reader _________________________ Date: ___________________74
Example 7: A train leaves Meerut station at 9:50 p.m. and reaches Kolkata at 5:30 a.m. the
next day. Find the duration of the journey. h min
Solution: Departure time of the train = 9:50 p.m. = 2150 hours 23 60
Time interval from 9:50 p.m. to 12 mid-night 24 00
= 2400 hours – 2150 hours – 21 50
= 0210 hours 2 10
= 2 hours 10 minutes
Time interval from 12 mid-night to 5:30 a.m., the next day
= 5 hours 30 minutes h min
So, total time taken = 2 h 10 min + 5 h 30 min 2 10
= 7 hours 40 minutes + 5 30
40
7
Thus, the duration of journey is 7 hours 40 minutes.
Note
Starting time + Duration = Finishing time Finishing time – Duration = Starting time
Practice Time 10B
1. Choose the correct option.
(a) 6 years 8 months + 8 years 6 months = ?
(i) 15 years 4 months (ii) 15 years 2 months
(iii) 14 years 8 months (iv) 14 years 4 months
(b) 9 hours 25 minutes – 3 hours 45 minutes = ?
(i) 5 hours 40 minutes (ii) 3 hours 35 minutes
(iii) 4 hours 15 minutes (iv) 4 hours 45 minutes
2. Add the following:
(a) 9 min 28 s and 6 min 16 s (b) 9 h 32 min and 6 h 26 min
(c) 2 days 17 h and 3 days 15 h (d) 5 weeks 4 days and 4 weeks 6 days
(e) 5 years 4 months and 3 years 7 months
3. Subtract the following:
(a) 20 min 48 s from 30 min (b) 15 min 33 s from 18 min 40 s
(c) 8 h 40 min from 24 h (d) 2 days 12 h from 4 days 20 h
(e) 3 weeks 5 days from 5 weeks 3 days (f) 15 years 9 months from 20 years
4. What time will it be:
(a) 3 h 45 min after 8:30 p.m.? (b) 5 h 30 min after 8:40 p.m.?
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