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Example 1: Convert 35°C to °F.
9
9 F = C × + 32
Solution: Multiply the °C temperature by . 5
5
7
9
35 × 9 = 7 × 9 = 63 = 35 × + 32
5 5 1
Now, add 32 to the product obtained to get the = (9 × 7) + 32
temperature in °F. = 63 + 32

Therefore, F = 63 + 32 = 95 F = 95°F

Thus, 35°C = 95°F
Fahrenheit (°F) to Celsius (°C)

To convert the temperature from °F to °C, subtract 32 from °F temperature and multiply

9
by . That is 5
5 C = (F – 32) × 9

Example 2: Convert 86°F to °C.

Solution: Subtract 32 from °F temperature. C = (F – 32) × 5

86 – 32 = 54 9 5

Now, multiply the difference by 5 to get the = (86 – 32) × 9
6
temperature in °C. 9 = 54 × 9 5 1
5
Therefore, C = 54 × = 6 × 5 = 30°C
9

= 6 × 5 = 30
Thus, 86°F = 30°C.

Example 3: The temperature of Jaipur is 45°C and temperature of Chennai is 132°F. Which
city is hotter and how much?

Solution: Given, temperature of Jaipur = 45°C and temperature of Chennai = 132°F.
Let us convert Jaipur's temperature into °F.

We have,
Project
9
°F = × °C + 32 1. Fill one glass with normal water and
5

9 the other with lukewarm water.
= × 45° + 32 2. Use a clinical Celsius thermometer to measure
5
= 81 + 32 = 113 their temperatures. Convert the recorded Celsius
temperature to their Fahrenheit equivalent.
Now, 45°C = 113°F 3. Verify your answer by measuring each

Since, 113°F < 132°F. temperature with a Fahrenheit thermometer.
Hence, Chennai is hotter than Jaipur by 19°F (132°F – 113°F).

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