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D:\Surender Prajapati\Books Final_CBSE and ICSE\ICSE\Preparatory_Stage_Maths-5_(31-10-2023)\Open_Files\CHAP_03
              \\November 3, 2023 11:27 AM   Surender Prajapati   Proof 5   Reader _________________________   Date: ___________________74





              Example 3: Find the LCM of 15, 20, 25 and 45 using division method.
              Solution:     We have 15, 20, 25 and 45.

                            Step 1:  Write 15, 20, 25 and 45 in a row.                            3 15, 20, 25, 45
                            Step 2:   Choose  the smallest suitable  prime  number,               5 5, 20, 25, 15

                                      which divides 15 and 45 exactly.                            2 1, 4, 5,       3
                            Step 3:   Write the  quotient  below  the  numbers  and  the          2 1, 2, 5,       3

                                      numbers which cannot divide by 3, bring it down             3 1, 1, 5,       3
                                      to the next row as it is.                                   5 1, 1, 5,       1
                            Step 4:   Next, the suitable prime number is 5; divide the                1, 1, 1,     1
                                      numbers by 5.

                            Step 5:   Continue dividing till you get 1 as quotient for all the numbers.

                                        Thus, the LCM of 15, 20, 25 and 45 = 3 × 5 × 2 × 2 × 3 × 5 = 900.
              Example 4: Find the LCM of:

                    (a)  20, 60 and 90                               (b)  24, 40 and 72

              Solution: (a)       2 20, 60, 90                       (b)   2 24, 40, 72
                                  2 10, 30 45                              2 12, 20, 36
                                  3 5, 15, 45                              2 6, 10, 18
                                  5 5, 5, 15                               3 3, 5,      9
                                                                                        3
                                                                           3 1, 5,
                                  3 1, 1,      3                           5 1, 5,      1
                                     1, 1,     1                               1, 1,    1

                               LCM = 2 × 2 × 3 × 3 × 5                  LCM = 2 × 2 × 2 × 3 × 3 × 5
                                      = 180                                   = 360

                       Practice Time 3F



                1.  Write the common multiples of each pair of numbers. Circle their smallest common
                    multiple.

                    (a)  12, 20          (b)  16, 24         (c)  14, 21          (d) 18, 30           (e)  10, 15
                2.  Find the LCM of these numbers using the common multiples method.

                    (a)  21, 28             (b)  48, 72              (c)  22, 110             (d)  60, 63

                    (e)  24, 36              (f)  38, 57             (g)  12, 15, 18          (h)  20, 30, 50
                     (i)  20, 32, 40         (j)  11, 22, 33         (k)  12, 15, 40          (l)  12, 16, 32

                3.  Find the LCM of these numbers using the prime factorisation method.

                    (a)  14, 17             (b)  51, 54              (c)  78, 82              (d)  25, 75
                    (e)  54, 90              (f)  24, 72             (g)  18, 20, 32          (h)  12, 16, 30

                     (i)  21, 24, 36         (j)  3, 15, 60          (k)  33, 55, 99          (l)  12, 18, 24


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