Basic HTML Version

|  | Table of Contents |  | View Full Version

Page 169 - Math_Genius_V1.0_C3_Flipbook
P. 169

    E:\Working\Focus_Learning\Math_Genius_3_(11-09-2024)\Open_Files\CHAP_09
                 \ 12-Sep-2024                      Surender Prajapati   Proof-5              Reader’s Sign _______________________ Date __________

                  Word probleMs

                  Example 1: Two ropes are 15 m 36 cm and 14 m 85 cm long. Find  their total length.
                   Solution:                                                       m        cm

                                                                                 1   1     1
                                Length of first rope                        =    1 5       3 6
                                Length of second rope                       = + 1 4        8 5
                                Total length of two ropes                   =    3 0       2 1

                                 Thus, the  total  length of the two ropes is 30 m 21 cm.

                  Example 2: A tree was 22 m 40 cm high. The upper part of the tree has been broken by
                  the wind, and the remaining height of the tree is 8 m 56 cm. Find the height of the tree
                  broken by the wind.
                   Solution:                                                        m       cm

                                                                                     11    13
                                                                                  1   1     3 10

                                Height of the tree                          =     2 2       4 0
                                Height of the remaining part of tree = –              8     5 6
                                Height of the upper part of the tree =            1 3       8 4

                                 Thus, 13 m 84 cm part of the tree is broken by the wind.

                  Example 3: Raghav bought two bags of sugar weighing, 18 kg 200 g and 32 kg 900 g
                  respectively. Find their total weight.
                   Solution:                                                      kg          g

                                                                                1   1
                                 Weight of the first bag of sugar          =    1 8       2 0 0
                                 Weight of the second bag of sugar         =  + 3 2       9 0 0

                                 Total weight of two bags of sugar =            5 1       1 0 0
                                Thus, the total weight of two bags of sugar is 51 kg 100 g.

                  Example 4: An empty basket weighs 11 kg 36 g, and the basket full of fruits weighs 29 kg.
                  How much fruit does it contain?
                   Solution:                                                     kg         g

                                                                                        9   9
                                                                                   8    10 10 10
                                Weight of fruits and basket              =     2 9      0 0 0

                                Weight of empty basket                   = – 1 1        0 3 6
                                Weight of fruits                         =     1 7      9 6 4

                                 Thus, the weight of fruits is 17 kg 964 g.

                  Mathematics-3                                                                                         167

| 164 165 166 167 168 169 170 171 172 173 174 |