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E:\Working\Focus_Learning\Math_Genius_3_(11-09-2024)\Open_Files\CHAP_04
\ 12-Sep-2024 Surender Prajapati Proof-5 Reader’s Sign _______________________ Date __________

Step 4: Add the numbers of boxes diagonally to find the 1 5 1 6
answer. While adding the numbers diagonally. 5 8 3

If the sum is of two digits, retain the ones and 1 2 2
carryover the tens to next diagonal and add with = 9 0 4 4
them. 2 + 5 + 1 + 1 0 4

Thus, 56 × 34 = 1904. 0 + 2 + 8 = 1

practice time 4D

1. Multiply the following:
(a) H t O (b) th H t O (c) th H t O (d) th H t O
2 1 4 2 2 3 7 3
× 3 4 × 4 2 × 5 6 × 6 4

+ + + +

(e) th H t O (f) th H t O (g) th H t O (h) th H t O
2 0 4 3 4 3 2 1 6 2 7 3
× 1 2 × 2 2 × 4 3 × 2 7

+ + + +

2. Write in the columns and find the product.

(a) 14 × 22 (b) 31 × 16 (c) 73 × 52 (d) 29 × 64
(e) 234 × 12 (f) 264 × 31 (g) 174 × 42 (h) 365 × 22
3. Multiply the following by using Lattice multiplication.

(a) 21 × 11 = _____ (b) 24 × 14 = _____ (c) 31 × 16 = _____

exploring Multiplication
Multiplying by expanding the bigger number

Example: Multiply: (a) 67 × 5 (b) 143 × 3
Solution: (a) Step 1: Write 67 as 60 + 7. (b) Step 1: Write 143 as 100 + 40 + 3.
Step 2: Multiply each term of Step 2: Multiply each term of

expanded form by 5 and expanded form by 3 and
add products obtained.
add products obtained. 100 × 3 = 300

60 × 5 = 300 40 × 3 = 120
7 × 5 = + 35 3 × 3 = + 9
335 429
Thus, 67 × 5 = 335. Thus, 143 × 3 = 429.

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