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E:\Working\Focus_Learning\Math_Genius_3_(11-09-2024)\Open_Files\CHAP_05
\ 12-Sep-2024 Surender Prajapati Proof-5 Reader’s Sign _______________________ Date __________
practice time 5c
Divide the following and check your answer.
1. 67 ÷ 6 2. 56 ÷ 5 3. 88 ÷ 4 4. 70 ÷ 7
5. 999 ÷ 9 6. 889 ÷ 8 7. 508 ÷ 5 8. 634 ÷ 3
Division by 1-Digit number (With regrouping)
Division of a 2-digit number
example 1: Divide 78 by 2.
Solution: Step 1. Arrange the numbers in long division form. 2 78 39 Q
Step 2. Divide 7 tens by 2. We know that 2 × 3 = 6 < 7 and 6
18
2 × 4 = 8 > 7. 18
0 R
So, write 3 in tens place in the quotient and 6
below 7.
Step 3. Subtract the digits of the tens column. 7 – 6 = 1
Step 4. Bring down 8 ones and regroup. 1 ten + 8 ones = 18 ones.
Step 5. Divide 18 ones by 2. Checking:
We have: 2 × 9 = 18, (Quotient × Divisor) + Remainder = Dividend
so write 9 in the ones (39 × 2) + 0 = 78
place of the quotient 78 + 0 = 78
78 = 78
and subtract Thus, the answer is correct.
18 – 18 = 0
Thus, quotient (Q) = 39, remainder (R) = 0.
Division of a 3-digit number
example 2: Divide 289 by 6.
Solution: Step 1. Divide 2 hundreds by 6. 2 < 6, so, 2 cannot be 6 289 48 Q
divided by 6. 24
So, regroup hundreds and tens. 49
48
2 hundreds + 8 tens = 28 tens 1 R
Step 2: Divide 28 tens by 6. Since 6 × 4 = 24 < 28 and 6 × 5 = 30 > 28.
So, write 4 in tens place of the quotient and 24 just below 28.
Step 3: Subtract: 28 tens – 24 tens = 4 tens
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