Page 175 - Math_Genius_V1.0_C5_Flipbook

E:\Working\Focus_Learning\Math_Genius_5_(05-10-2023)\Open_Files\CHAP_08
\\November 22, 2023 4:46 PM Surender Prajapati Proof 5 Reader _________________________ Date: ___________________74

Solution: (a) First, convert the given measurements into metres.

24 m 24 cm 7 m 12 mm

We have, 100 cm = 1 m We have, 1000 mm = 1 m

So, 24 cm = 0.24 m So, 12 mm = 0.012 m
Therefore, 24 m 24 cm = 24.24 m Therefore, 7 m 12 mm = 7.012 m

Now, add 24.24 m Alternative method:
and 7.012 m We can write 24.24 m as 2 dam 4 m 2 dm

4 cm. Similarly, 7.012 m as 7 m 0 dm 1 cm 2
24.240 m mm. Now, add them as: dam m dm cm mm
+ 7.012 m 2 4 2 4 0
31.252 m + 7 0 1 2
3 1 2 5 2

(b) 3 kg 7 hg 5 dag 3 g 4 dg 5 cg 2 mg 3753.452 g

+ 5 kg 7 hg 2 dag 0 g 1 dg 4 cg 4 mg or + 5720.144 g
9 kg 4 hg 7 dag 3 g 5 dg 9 cg 6 mg 9473.596 g

(c) 15 L 725 mL = 15.725 L and 11 L 850 mL = 11.850 L
Alternative Method:

15 . 725 L L mL
15
+ 11 . 850 L + 11 725
850
27 . 575 L 27 575

15 L 725 mL + 11 L 850 mL = 27 L 575 mL
example 2: Subtract the following.

(a) 2 km 145 m from 9 km 23 m (b) 5 kg 165 g from 7 kg 250 g
(c) 10 L 75 mL from 24 L 800 mL

Solution: (a) First, convert the given measurements into kilometres.
2 km 145 m 9 km 23 m

1000 m = 1 km 1000 m = 1 km

145 m = 0.145 km 23 m = 0.023 km
2 km 145 m = 2.145 km 9 km 23 m = 9.023 km

Now, subtract 2.145 km from 9.023 km.

9.023 km Alternative Method:
m
– 2.145 km km 023
9
6.878 km –2 145
6 878

Mathematics-5 173