Page 198 - Math_Genius_V1.0_C5_Flipbook

E:\Working\Focus_Learning\Math_Genius_5_(05-10-2023)\Open_Files\CHAP_09
\\November 23, 2023 10:50 AM Surender Prajapati Proof 5 Reader _________________________ Date: ___________________74

example 1: Convert 35°C to °F. 9
9
Solution: Multiply the °C temperature by . F = C × + 32
5
9 5 7 9
35 × = 7 × 9 = 63 = 35 × + 32
5 5 1
Now, add 32 to the product obtained to get the = (9 × 7) + 32
temperature in °F. = 63 + 32

Therefore, F = 63 + 32 = 95 F = 95°F

Thus, 35°C = 95°F
fahrenheit (°f) to Celsius (°C)

To convert the temperature from °F to °C, subtract 32 from °F temperature and multiply

9
by . That is 5
5 C = (F – 32) ×
9

example 2: Convert 86°F to °C.

Solution: Subtract 32 from °F temperature. 5
C = (F – 32) ×
86 – 32 = 54 9 5

Now, multiply the difference by 5 to get the = (86 – 32) × 9
6
9
temperature in °C. = 54 × 9 5 1
Therefore, C = 54 × 5 = 6 × 5 = 30°C
9

= 6 × 5 = 30
Thus, 86°F = 30°C.

example 3: The temperature of Jaipur is 45°C and temperature of Chennai is 132°F. Which
city is hotter and how much?

Solution: Given, temperature of Jaipur = 45°C and temperature of Chennai = 132°F.
Let us convert Jaipur's temperature into °F.

We have,
Project
9
°F = × °C + 32 1. Fill one glass with normal water and
5
9 the other with lukewarm water.
= × 45° + 32 2. Use a clinical Celsius thermometer to measure
5
= 81 + 32 = 113 their temperatures. Convert the recorded Celsius
temperature to their Fahrenheit equivalent.
Now, 45°C = 113°F 3. Verify your answer by measuring each

Since, 113°F < 132°F. temperature with a Fahrenheit thermometer.
Hence, Chennai is hotter than Jaipur by 19°F (132°F – 113°F).

196 Mathematics-5