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E:\Working\Focus_Learning\Math_Genius_5_(05-10-2023)\Open_Files\CHAP_02
\\February 27, 2024 10:04 AM Surender Prajapati Proof 5 Reader _________________________ Date: ___________________74

example 3: Divide the following and check your answer.
(a) 26736 ÷ 125 (b) 303683 ÷ 260

Solution: 2 1 3 Q Step 1: Divide 267 by 125. 125 × 2 = 250 is the
(a) 125 2 6 7 3 6 maximum possible product obtained < 267.
– 2 5 0 Subtract 250 from 267 and bring down 3.

1 7 3 Step 2: 173 is the new dividend. Here, 125 × 1 = 125 is
– 1 2 5 the maximum possible product obtained < 173.
4 8 6 Subtract 125 from 173 and bring down 6.
– 3 7 5 Step 3: Now, 486 is the new partial dividend. Here, 125 ×

1 1 1 R 3 = 375 is the maximum possible product < 486.
Subtract 375 from 486.
Step 4: 111 is left which is less than 125 and nothing

is left to bring down.
Checking: Thus, Quotient = 213 and Remainder = 111

Quotient × Divisor + Remainder = Dividend
213 × 125 + 111 = 26736
26625 + 111 = 26736

26736 = 26736. The division is correct.

(b) 1 1 6 8 Q Step 1: Divide 303 by 260.
260 3 0 3 6 8 3 260 × 1 = 260 is the maximum possible product
– 2 6 0
obtained < 303.
4 3 6 Subtract 260 from 303 and bring down 6.
– 2 6 0

1 7 6 8 Step 2: 436 is the new dividend. Here, 260 × 1 = 260 is
– 1 5 6 0 the maximum possible product obtained < 436.

2 0 8 3 Subtract 260 from 436 and bring down 8.
– 2 0 8 0 Step 3: 1768 is the new dividend. Here, 260 × 6 = 1560

3 R
is the maximum possible product obtained
< 1768. Subtract 1560 from 1768 and bring
down 3.

Step 4: Now, 2083 is the new partial dividend. Here,
260 × 8 = 2080 is the maximum possible

product < 2083. Subtract 2080 from 2083.
Step 5: 3 is left which is less than 260 and nothing is

left to bring down.
Thus, Quotient = 1168 and Remainder = 3

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