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E:\Working\Focus_Learning\Math_Genius_5_(05-10-2023)\Open_Files\CHAP_04
              \\November 22, 2023 3:12 PM   Surender Prajapati   Proof 5   Reader _________________________   Date: ___________________74





                                                                  12
              example 2:  Find two equivalent fractions of            .
                                                                  18
                                        12     12 ÷ 2     6      12     12 ÷ 3     4          Think and Answer
              Solution:     We have,        =          =   and       =          =
                                        18     18 ÷ 2     9      18     18 ÷ 3     6          3   =  12   =
                                     6       4                                 12                  20    45
                            Hence,  and   are equivalent fractions of             .
                                     9       6                                 18

              rEducing a Fraction to its lowEst tErMs


              A fraction  is  said  to be  in  its  lowest  term  (or simplest  form),  if  the  numerator and  the
              denominator of the fraction have no common factor except 1.
              To reduce a fraction to its lowest term, the numerator and the denominator of the fraction
              are divided by their HCF.

              example:      Reducing the following fractions to their simplest form.
                        108                                              135
                    (a)                                              (b)
                        126                                              300
              Solution:     (a)  First, we find the HCF of the numerator 108 and the denominator 126.
                                   2 108        2 126
                                   2 54         3 63
                                   3 27         3 21
                                   3   9        7    7
                                   3   3             1
                                       1

                                 Clearly, 108 = 2 × 2 × 3 × 3 × 3 and 126 = 2 × 3 × 3 × 7.
                                 Therefore, HCF of 108 and 126 = 2 × 3 × 3 = 18.

                                 Now,   108   =   108 ÷ 18   =   6
                                        126      126 ÷ 18      7

                                 Thus,   6   is the simplest form of   108 .
                                         7                             126
                            (b)  First, we find the HCF of the numerator 135 and the denominator 300.
                                   3 135         2 300
                                   3 45          2 150                                Think and Answer
                                   3 15          3 75
                                   5   5         5 25                               Is every unit fraction
                                       1         5    5                             in its simplest form?
                                                      1

                                 Clearly, 135 = 3 × 3 × 3 × 5 and 300 = 2 × 2 × 3 × 5 × 5.
                                 Therefore, HCF of 135 and 300 = 3 × 5 = 15.

                                        135      135 ÷ 15       9
                                 Now,         =              =
                                        300      300 ÷ 15       20

                                 Thus,    9   is the simplest form of    135  .
                                         20                              300


              Mathematics-5                                                                                          85
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