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Example 13: The floor of a bathroom is 400 cm long and 2 m 50 cm wide. It is to be covered
completely by square tiles of side 50 cm. Find the cost of the tiling at the rate of `90 per tile.

Solution: Length of the bathroom = 400 cm and its breadth = 2 m 50 cm = 250 cm

So, area of the floor of the bathroom = 400 cm × 250 cm = 1,00,000 sq. cm
Side of a square tile = 50 cm

So, area of a square tile = 50 cm × 50 cm = 2500 sq. cm

Then, number of square tiles needed to cover the floor completely
,
,
Area of the floor 100 000 sq. cm
= = = 40
Area of a tile 2500 sq. cm
Now, cost of tiling at the rate of `90 per tile = `90 × 40 = `3600.

Example 14: Find the area of the given figures by splitting them into rectangles/squares. (The
measures are given in centimetres).

3 1

5 2
2
(a) 3 3 (b)
2 4
4
1 1 3

3
Solution: (a) We can split the given figure into three rectangles, say 5

A(2 cm by 1 cm), B(5 cm by 1 cm) and C(2 cm by 1 cm). 1 B 1
3
So, the area of the given figure = Area of rectangle A + Area of 2 A 2 C
rectangle B + Area of rectangle C
1 1
= (2 cm × 1 cm) + (5 cm × 1 cm) + (2 cm × 1 cm)

= (2 + 5 + 2) sq. cm = 9 sq. cm
(b) We can split the given figure into two squares, say A (3 cm by 3 cm) and C (3 cm by
3 cm) and two rectangles say B (2 cm by 1 cm), and D (4 cm by 2 cm).

3 1

2 D 4
2 C
1 B 1
1 2 2

3 A 3

3

187 Perimeter and Area
187
and Ar
ea
P
erimeter