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Solution: (a) Using the given measurements, we can find out the length/width of some portions
as shown in the diagram given below:
48 ft

Toilet
Kitchen
(6 ft × (20 ft × 10 ft)
10 ft) Area = 80 sq. ft (8 ft × 10 ft) Utility 10 ft
Master Bedroom Area = Area = 200 sq. ft
(14 ft × 16 ft) 60 sq. ft
Area = 224 sq. ft

Hall
(26 ft × 18 ft) 18 ft
Small Bedroom Area = 468 sq. ft Area = 144 sq. ft (8 ft × 18 ft) Entrance
(14 ft × 12 ft)
Area = 168 sq. ft

14 ft 26 ft 8 ft
Toilet: (6 ft × 10 ft) ⇒ Area = 60 sq. ft

Utility: (8 ft × 10 ft) ⇒ Area = 80 sq. ft
Entrance: (8 ft × 18 ft) ⇒ Area = 144 sq. ft
Small Bedroom: (14 ft × 12 ft) ⇒ Area = 168 sq. ft

Hall: (26 ft × 18 ft) ⇒ Area = 468 sq. ft
(b) Total area of the house = 48 ft × 28 ft = 1344 sq. ft
Practice Time 6D

1. Find the area of the given figure by splitting it into rectangles and triangles. Further, make any
irregular figure whose area is approximately half of the given figure.

2. Write the dimensions of a rectangle whose area is the sum of the areas of two rectangles having
measurements: 6 cm × 8 cm and 5 cm × 10 cm.
3. Write the side of a square whose perimeter is the sum of the perimeters of two rectangles with
measurements: 10 cm × 9 cm and 6 cm × 7 cm.
4. Draw a rectangle of size 16 units × 12 units. Draw another rectangle inside it, without touching the
outer rectangle, that occupies exactly half the area.

193 Perimeter and Area
193
and Ar
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P
erimeter