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\ 07-Nov-2024 Bharat Arora Proof-8 Reader’s Sign _______________________ Date __________

For example, let the number be 27. Its reverse = 72

The sum of the number + its reverse number = 27 + 72 = 99, which is a single-step palindrome.
For example, if we begin with number 89, we will end up with a palindrome in 24 steps.

89 + 98 = 187 A Pinch of History
187 + 781 = 968 Mahavira, is one of the most celebrated
968 + 869 = 1837 Indian mathematicians of the 9th century.

1837 + 7381 = 9218 His major work Ganita Sara Sangraha, was
9218 + 8129 = 17347 written around 850 ACE. In chapter 2, Shloka
17347 + 74371 = 91718 10-20, he described different combinations
of numbers.
91718 + 81719 = 173437
uSUnkU;`rq'kjprqf[k}U}SoaQ LFkkI;e=k uoxqf.kre~A
173437 + 734371 = 907808
vkpk;ZegkohjS% dfFkra ujikydf.BdkHkj.ke~~ AAûúAA
907808 + 808709 = 1716517
"kV~f=koaQ i×p"kV~oaQ p lIr pknkS çfrf"Bre~A
1716517 + 7156171 = 8872688
=k;fL=ka'kRlaxqf.kra d.BkHkj.kekfn'kSr~ AAûûAA
8872688 + 8862788 = 17735476
17735476 + 67453771 = 85189247 (i) Write the number 12345679 and
multiply it by 9 to get a necklace of
85189247 + 74298158 = 159487405
number 1.
159487405 + 504784951 = 664272356
12345679 × 9 = 11,11,11,111
664272356 + 653272466 = 1317544822
(ii) Write the digit 3 six times, followed by
1317544822 + 2284457131 = 3602001953 digit 6 five times and then the digit 7
3602001953 + 3591002063 = 7193004016 in ascending order and multiply by 33

7193004016 + 6104003917 = 13297007933 to get a necklace.
13297007933 + 33970079231 = 47267087164 333333666667 × 33 = 1,10,00,01,10,00,011

47267087164 + 46178076274 = 93445163438 He also mentioned a few other numbers in
93445163438 + 83436154439 = 176881317877 the same shlokas:
176881317877 + 778713188671 = 955594506548 142857143 × 7 = 1,00,00,00,001
955594506548 + 845605495559 = 1801200002107 37037037 × 3 = 11,11,11,111

1801200002107 + 7012000021081 = 8813200023188 11011011 × 91 = 1,00,20,02,001
Example 8: Read the clues given below and solve the puzzle:

• I am a 5-digit palindrome.
• I am an odd number. TTh Th H t O
• My ‘T’ digit is double of my ‘O’ digit.

• My ‘H’ digit is double of my ‘T’ digit.
Who am I? Write the number in words.

Solution: The required 5-digit odd palindrome number is 12421, TTh Th H t O
where the ‘T’ digit is double the ‘O’ digit and the ‘H’ digit is double 1 2 4 2 1
the ‘T’ digit.

In words: Twelve thousand four hundred twenty-one.

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