Page 185 - Math_Genius_V1.0_C7_Flipbook
P. 185

D:\Surender Prajapati\CBSE_ICSE_Book_New\CBSE\Grade-7\Math_Genius-7\Open_File\08_Chapter\08_Chapter
               \ 15-Nov-2024                      Surender Prajapati   Proof-6             Reader’s Sign _______________________ Date __________





                Pythagorean Triple

                If three numbers are such that the square of the largest one is equal to the sum of the squares of
                other two, then they are known as Pythagorean Triples.
                The few examples of Pythagorean Triples are:                                        Quick Check
                                                             2
                                                        2
                                                   2
                  (i)  3, 4, 5                    [5  = 3  + 4 ]                                 Find the value of k, if
                                                         2
                                                     2
                                                               2
                 (ii)  5, 12, 13                  [13  = 5  + 12 ]                               (8, 15, k) is a Pythagorean
                                                     2
                                                               2
                                                         2
                  (iii) 7, 24, 25                 [25  = 7  + 24 ]                               triplet.
                Example 12: DABC is right-angled at C. If AC = 6 cm and BC = 8 cm, find the length of AB.
                Solution:  In right-angled triangle ABC, right-angled at C, by Pythagoras property,
                                2
                                      2
                            AB  = AC  + BC  2                                                   A
                                    2
                                2
                            AB  = 6  + 8 2
                                2
                            AB  = 36 + 64                                                       6 cm      ?
                                2
                            AB  = 100
                                2
                            AB  = 10 × 10                                                       C        8 cm          B
                                     2
                                2
                            AB  = 10 . So, AB = 10
                Thus, the length of the side AB = 10 cm.
                Example 13: Find the value of x in the following:
                                  A
                                                                                     B
                                                                                          12 cm
                           (a)  x m      26 m                             (b)   x cm
                                                                                               C
                                                                                 A    15 cm
                                  B    24 m   C

                Solution: (a)  In right-angled triangle ABC, right-angled at B,  by Pythagoras property,
                                  2
                                         2
                                AC  = AB  + BC 2
                                        2
                                  2
                                26  = AB  + 24 2                                                           A
                                  2
                                AB  = 676 – 576
                                  2
                                AB  = 100                                                               x m       26 m
                                  2
                                AB  = 10 × 10
                                AB  = 10 2                                                                  B   24 m   C
                                  2
                                So, AB = 10 m
                                Thus, x = 10
                           (b)  In right-angled triangle ABC, right-angled at B, by Pythagoras property,
                                         2
                                  2
                                AC  = AB  + BC 2
                                15  = x  + 12 2
                                  2
                                      2
                                  2
                                AB  = 225 – 144                                                               B
                                AB  = 81                                                               x cm       12 cm
                                  2
                                AB  = 9 × 9                                                                            C
                                  2
                                AB  = 9 2                                                                A    15 cm
                                  2
                                So, AB = 9 m
                                Thus, x = 9

                                                                  183                         The Triangle and Its Properties
   180   181   182   183   184   185   186   187   188   189   190