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                Example 10: Arrange the following ratios in ascending order.

                            2 : 5, 3 : 10, 5 : 8, 1 : 3
                                  2                3           5           1
                Solution: 2 : 5 =  ;      3 : 10 =   ;  5 : 8 =  ;  1 : 3 =
                                  5               10           8           3
                LCM of the denominators 10, 8, 5 and 3 is 120. Then,

                             2  =  2 ×  24  =  48  ;  3  =  3 ×  12  =  36
                             5    5 ×  24  120     10   10 ×  12   120

                             5  =  5 ×  15  =  75  ;  1  =  1 1 ×  40  =  40
                             8    8 ×  15  120      3    3 ×  40  120
                Q           75 > 48 > 40 > 36

                              75    48     40     36
                \                >      >      >
                             120    120    120    120
                              5   2    1    3
                                >   >    >
                              8   5    3   10

                Thus, 5 : 8 > 2 : 5 > 1 : 3 > 3 : 10

                Division of a Given Quantity in a Given Ratio


                On Dussehra, Shreya’s grandparents gave her `800 to visit the Mela to
                celebrate the festival. They asked her to divide the money with her
                younger brother Rohan in the ratio 3 : 2.

                How will she divide the money with Rohan in the given ratio?
                Clearly, there are a total of 5 parts, in which Shreya gets 3 parts of
                the amount and Rohan gets 2 parts of the amount.

                So, to divide the given quantity in a given ratio, we find the sum of
                the terms of the ratio and proceed as follows. Sum of the terms of
                given ratio = 3 + 2 = 5
                                                             3
                Therefore,  Shreya’s part of the amount =   × `800 = `480
                                                             5
                                                     2
                And Rohan’s part of the amount =   × `800 = `320
                                                     5
                Example 11: Divide `6288 between A, B and C in the ratio 3 : 4 : 5.

                Solution: We have, total amount =  `6288
                Sum of the terms of the ratio = 3 + 4 + 5 = 12
                                                     3                             Think and Answer
                Therefore,          A’s share =  `   12 × 6288  = `1572
                                                              
                                                     4                         A chocolate box has 21 chocolate balls
                                                                                 which are to be distributed between you
                                    B’s share =  `   12 × 6288  = `2096       and your sibling in the ratio 3:4. What
                                                              
                                                     5                         number of chocolate balls will you and
                                    C’s share =  `   12 × 6288  = `2620       your sibling get?
                                                              


                                                                  205                                 Ratio and Proportion
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