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               \ 15-Nov-2024                      Surender Prajapati   Proof-6             Reader’s Sign _______________________ Date __________





                                 121                        121          200    11 200     200       2
                                                                                   ×
            Solution: (a)  11 ÷       = 11 × Reciprocal of        = 11 ×      =          =      =  18
                                 200                        200          121      121       11       11
                                                                         ×
                                                                                 ×
                            3   5    3                   5    3   8    38      32      6     1
                        (b)   ÷    =   × Reciprocal of   =   ×   =           =       =   =  1
                                                                                 ×
                            4   8    4                   8    4   5    4 ×  5  15      5     5
                                                                          ×
                              1   2    9                   2   9   7    97      63     7
                        (c)   2  ÷   =   × Reciprocal of     =   ×    =       =    =  7
                                                                          ×
                              4   7    4                   7   4   2    42      8      8
                    Enrichment
                Simplification of Fractions
                We have already studied how to simplify whole numbers and integers by involving various fundamental
                operations together. Here, we shall study and simplify the fractions involving various operations (+, –, ×, ÷
                and of), making use of specific order.
                                       3
                Let us simplify   15+     1 of ÷  1   −  17  .
                                       4 4
                                   2
                                               8
                         1  3  1  17      1 3 4   17                                         QReciprocalof  1  is 4 
                             ÷
                                             × ×
                   15+   2  of  4 4   −  8  =15+   2 4 1   −  8                                     4    
                                          1  3  1 17×  ×   3  17
                                     =15+        −   =15+ −                                  (Q LCM of 2 and 8 is 8)
                                             2     8      2   8
                                                             −
                                                                 ×
                                                    ×
                                                          ×
                                      15 3   17   15 8+3 4 17 1
                                     =   + −    =
                                       1  2   8           8
                                             −
                                      120+1217     115     3
                                     =           =     =14
                                           8        8      8
                Simplify the following.
                           
                                                                                              
                                    1
                             1
                        1 
                                            
                  (a)   3 ÷  1 −  1  2 −  1  −  1                     (b)   5  −          3  of   4  ÷   7  +    23 − 1 2 
                                                                                              
                                                                                           +
                                            
                        4     4  2    2  4  6             7         16  5  10  12  3 3 
                                                                                              
                                            
                     Practice Time 2C
              1.  Write the reciprocal of the following fractions:
                     2                      4                    2                 5    4                3
                 (a)                   (b)                 (c)  2             (d)     +          (e)  5 ×
                     3                      7                    9                 4    5                5
              2.  Divide the following fractions:
                        2                              2                                 2
                 (a)  5 ÷                         (b)     ÷ 6                      (c)  1 ÷  2
                        3                              15                                5
                      1                                      3                                1
                (d)  2 ÷  15                      (e)  15 2÷                       (f)  36 1÷
                      7                                      5                                17
              3.  Find the quotient.

                     4   7                      1  7                    2    1                    1   7
                 (a)   ÷                  (b)  2 ÷                 (c)  6 ÷  4             (d)  13 ÷
                     3   5                      7   2                   3    5                    6   21
                      1     1                   1     1                 5    1
                 (e)  7 ÷ 8               (f)  3 ÷  4             (g)  2 ÷  8
                      8    16                   4    28                 8    6


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