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               \ 15-Nov-2024                      Surender Prajapati   Proof-6             Reader’s Sign _______________________ Date __________





                                                                         2
                                                                             4
                                                                                  6
                                                               6
                                                        2 2
                                                   2
                                                 2 × ( 3 )  × 3 × 2 8  2 ×  3 ×  3 × 2 8
                                                                                                                 m
                                                                                                                      m
                                                                                                            m
                                                                                             m n
                                                                                                    mn
                                               =                     =                  [Q(a )  = a , (ab)  = a  × b ]
                                                          3
                                                                         6
                                                                                  4
                                                                             3
                                                  2 (  23  × 3 ×  2 × 3 4  2 × 3 ×  2 × 3 4
                                                               4
                                                     )
                                                 2 28  ×  3 46  2 ×  3 10
                                                   +
                                                                10
                                                         +
                                                                                                           m
                                                                                                                n
                                               =            =                                         [Q a × a  = a m+n ]
                                                 2 64  ×  3 34  2 ×  3 7
                                                                10
                                                   +
                                                         +
                                                                       3
                                                                                                           m
                                                                                                                n
                                                                  0
                                               = 2 10 – 10  × 3 10 – 7  = 2  × 3  = 1 × 27 = 27       [Q a ÷ a  = a m–n ]
                                                                 (
                                                                       4
                                 2 × a 3  ×  5a 4  22××  2 × 5  × a 3  × a )  22×× a 3+4
                                  3
                                                                                                               n
                                                                                                          m
                           (b)                =                           =                          [Q a  × a  = a m + n ]
                                     10 a 2             2  × 5  × a 2            a 2
                                                 22×× a  7
                                                                                                               n
                                                                   −
                                                             4
                                                                                                          m
                                               =           =× a   72  = a 4  5                       [Q a  ÷ a  = a m – n ]
                                                     a 2
                                                                                                                 4
                                                             6
                Example 18: By what number should (–2)  be multiplied so that the product is equal to (4) ?
                                                                                 6
                Solution: To get the required number, divide the (4)  by (–2) . Therefore,
                                                                        4
                                             4
                  The required number = (4)  ÷ (–2) 6
                                            2 4
                                         = (2 )  ÷ (–2)                                                  [Q (a )  = a ]
                                                                                                              m n
                                                     6
                                                                                                                     mn
                                             8
                                                                                            6
                                         = (2)  ÷ (2) 6                              [Q (–1)  = 1, as 6 is even number]
                                         = 2 8 – 6
                                         = 2 2
                 Thus, the required number = 4
                Example 19: By what number should 5  be divided to obtain 625?
                                                          25
                Solution:  To get the required number divide 5  by 625. Therefore,
                                                                  25
                                            25
                 The required number = 5  ÷ 625
                                         = 5  ÷ 5 4
                                            25
                                         = 5 25 – 4  = 5 21
                Thus, the required number is 5 .
                                                  21
                        Enrichment
                    If on both the sides, powers have the same base. So, their exponents must be equal.
                    Let us take an example based on the above statement.
                                      5
                                               
                                         5
                                    5
                                                5
                    Find x so that      ×    11  =   8x
                                         
                                    
                                                
                                    3
                                         3
                                                3
                                      3
                                               
                                                5
                                         5
                                    5
                    Given,            ×     11  =   8x
                                    
                                                
                                         
                                    3
                                                3
                                         3
                                                5
                                               
                                                                                                                    m
                                                                                                              a
                                                                                                            
                       So,             5 5  × 5 11  =    8x                                           Using   m  =  a 
                                                                                                       
                                                                                                                     
                                                3
                                       3 5  3 11                                                              b 
                                                                                                              b
                                                                                                                    m
                                         ×
                                        5
                                       55  11    5  8x           (5) 16   5 8x
                                                                                                       m
                                                                                                            n
                      or                     =     or                =                      [Using a  × a  = (a) m + n ]
                                         ×
                                        5
                                                3
                                       33  11                    (3) 16   
                                                                          3
                                         5
                                                5
                                               
                      or                   16  =    8x   or     16 = 8x
                                                
                                         
                      Thus, 8x = 16      3      3
                      Therefore, x = 2
                                         3
                                                 
                                       2
                                            2
                                                  2
                       Find m so that      ×    6  =   2m-1
                                                  
                                      
                                            
                                                  9
                                       9
                                            9
                                                                   89                                Exponents and Powers
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