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\ 15-Nov-2024 Surender Prajapati Proof-6 Reader’s Sign _______________________ Date __________

Chapter assessment
A. Choose the correct option.

17
1. (−1) =
(a) 1 (b) –1 (c) 17 (d) –17
2. (−2) × (−2) × (−2) × (−3) × (−3) =

2
3
2
(a) (−2) × (−3) 3 (b) (−2) × (−3) 3 (c) (−2) × (−3) 2 (d) 2 × 3 3
3. [(−2) ] =
3 0
(a) 2 (b) –2 (c) 1 (d) –1
4. (−1) ÷ (−1) =
16
5
(a) 1 (b) –1 (c) 11 (d) 0

8 + 8 20
22
5. The value of is
8 20
2
2
(a) 8 2 (b) 8 42 (c) 8 + 1 (d) 8 + 8
3
3
6. (−2) × (−3) =
(a) (–6) 3 (b) 6 6 (c) 6 5 (d) 6 3
7. Among the following numbers, the number which is in the standard form is

(a) 2.7 × 10 6 (b) 27 × 10 5 (c) 270 × 10 4 (d) 0.27 × 10 7
8. The number 32100000 in standard form is

(a) 321 × 10 5 (b) 32.1 × 10 6 (c) 3.21 × 10 6 (d) 3.21 × 10 7
B. Assertion and Reason Type Questions.

In the following questions, a statement of Assertion (A) is followed by a statement of Reason (R).
Choose the correct option as:
(a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion
(A).

(b) Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of
Assertion (A).

(c) Assertion (A) is true but Reason (R) is false.
(d) Assertion (A) is false but Reason (R) is true.
1. Assertion (A): 3 × 3 = 3 7 + 8 = 3 15
8
7
Reason (R): In multiplication if the base is same then exponents is added.
2. Assertion (A): The standard form of 4285.3 is 4.2853 × 10 .
3
Reason (R): Any number can be expressed as a decimal number between 1.0 and 10.0 (including
1.0) multiplied by a power of 10. Such a form of a number is called its standard form.
n
3. Assertion (A): 3 × 2 = 24, then n = 3
Reason (R): If on both the sides, powers have the same base. So, their exponents must be equal.

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