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Solution: (a) Draw two perpendicular
axes and label: height on the
x-axis and number of
students on y-axis.
( b) Represent each interval
by 5 small divisions along
horizontal axis.

( c) Since the scale on the
horizontal axis starts at 120,
a kink (break) is indicated
near the origin to show that
the graph is drawn to scale
beginning from 120 and not
from the origin.

( d) Take height of rectangle
proportional to the corres-
ponding frequencies.

Example 5: Look at the adjoining
histogram and answer the questions
given below.
( a) Make a frequency
distribution table.
( b) In which class interval
do the maximum
students score?

( c) How many students
have scored less than
50 marks?

( d) Find the number of
students who scored
70 or more marks.
Solution: (a) We can tabulate the
frequency distribution
from the given histo-
gram as shown below.

Score 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90-100
Number of
students 1 2 1 2 6 9 13 5

( b) The maximum students have scored in the class interval 80-90.
( c) The number of students who have scored less than 50 = 1 + 2 + 1 = 4

( d) The number of students who have scored 70 or more = 9 + 13 + 5 = 27

Mathematics-8 102