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                 \ 06-Jan-2025  Bharat Arora   Proof-7             Reader’s Sign _______________________ Date __________





                Finding the Square of a Number


                We can easily find the square of one-digit and smaller two-digit numbers. But when the number
                becomes larger, it becomes laborious and time consuming. Let us see some methods to find the
                square of numbers quickly, without doing the actual multiplication.
                Let us find square of 46.                                                          Quick Check

                We know that               46 = 40 + 6                                          Find the square of:
                                             2
                                                        2
                Therefore,                46  = (40 + 6)  = (40 + 6) × (40 + 6)                 1. 58         2. 73
                                                                          2
                                              = 40(40 + 6) + 6(40 + 6) = 40  + 40 × 6 + 6 × 40 + 6 2
                                              = 1600 + 240 + 240 + 36 = 2116

                Square of Natural Numbers Ending with 5

                Observe the following:

                                             2
                                          25  = 625 = (2 × 3) hundreds + 25
                                             2
                                          35  = 1225 = (3 × 4) hundreds + 25
                                             2
                                         125  = 15625 = (12 × 13) hundreds + 25
                Thus, we can find the square of numbers with unit digit 5, easily as follows:

                First we cross out 5 and multiply the remaining numbers by its successor, and at last suffix 25 to
                the product to obtain the square.
                                             2
                Moreover,               (a5)  = (10a + 5)² = (10a + 5) (10a + 5)
                                              = 10a × 10a + 10a × 5 + 5 × 10a + 5 × 5

                                              = 100a  +100a + 25 =  100a (a + 1) + 25
                                                     2
                                              = a(a + 1) hundreds + 25

                Example 17: Find the square of the following:
                           (a)  95                   (b)  105              (c)  525

                                  2
                Solution: (a)  95  = 9 (9 + 1) hundreds + 25 = (9 × 10) hundreds + 25 = 9000 + 25 = 9025
                                   2
                           (b)  105  = 10(10 + 1) hundreds + 25 = (10 × 11) hundreds + 25 = 11025
                                   2
                           (c)  525  = 52(52 + 1) hundreds + 25 = (52 × 53) hundreds + 25 = 275600 + 25 = 275625
                Pythagorean Triplets


                In earlier class, we learnt that 3 cm, 4 cm and 5 cm are the side lengths of a right-
                angled triangle because
                                                                                                                5      4
                             3  + 4  =  9 + 16 = 25 = 5 2
                                   2
                              2
                The set of three numbers such as 3, 4 and 5 is known as Pythagorean triplet. A set
                                                                                        2
                                                                                            2
                of three numbers a, b and c is called a Pythagorean Triplet if a  + b  = c .                     3
                                                                                    2
                Some other examples of Pythagorean triplets are 5, 12, 13 and 9, 12, 15.
                                                                               2
                                                                                                           2
                                                                                             2
                                                             2
                                                      2
                For any natural number m > 1,  (2m)  + (m  – 1)  = (m  + 1) . So, 2m, (m  – 1) and (m  + 1) form a
                                                                         2
                                                                   2
                Pythagorean triplet.
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