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Example 19: Harshit gave his car for service at a service station, and he was charged as follows:
(a) 3.5 litres of engine oil @ `320 per litre and GST@18%.
(b) `2,150 for all other parts and GST @ 12%.
(c) `2,580 as labour charges and service tax @18%.
(d) 3% cess on service tax.
Find the total bill amount.
Solution: (a) Cost of 3.5 litres of engine oil @ `320 per litre = 3.5 × `320 = `1120
18
GST on engine oil = 18% of `1120 = × `1120 = `201.60
100
12
(b) GST on other parts = 12% of `2150 = × `2150 = `258
100
18
(c) Service tax on labour charges = 18% of `2580 = × `2580 = `464.40
100
3
(d) 3% cess on service tax = 3% of `464.40 = × `464.10 ≈ `13.93
100
Thus, the total bill amount = (`1120 + `201.60) + (`2150 + `258) + (`2580 + `464.40) + `13.93 = `6787.93
Example 20: The marked price of a printer is `9,500. The shopkeeper offers a discount of 8% on
cash payments. If Vinay paid `9788.80 including GST, find the rate of GST imposed on the printer.
Solution: MP = `9500, and discount = 8%
−
100 8 92
SP = × `9500 = × 9500 = `8740
100 100
Now, the total bill amount including GST = `9788.80
So, GST = `9788.80 – `8740 = `1048.80
.
GST 1048 80
Hence, the rate of GST = × 100 = × 100 = 12%
SP 8740
Example 21: The list price of a cooler is `12508. The rate of GST is 18%. The customer requests
the shopkeeper to reduce the price of the cooler (i.e., allow discount in the price of the cooler) is
such an extent that the price remains `12508, including the GST. Find the reductions needed in
the price of the cooler.
Solution: List price of the cooler = `12508
Let the reduced price of the cooler be `x
Selling price of the cooler = `x + 18% GST on `x
18
⇒ `12508 = `x + ` 100 × x
118x
⇒ `12508 =
100
12508 × 100
⇒ x = ` = `10,600
118
So, reduction needed in the price of the cooler = `(12508 – 10600) = `1908
Mathematics-8 178
