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                 \ 06-Jan-2025  Bharat Arora   Proof-7             Reader’s Sign _______________________ Date __________





                Rate of growth (R) = 2% p.a., Time (T) = 2 years

                                                         R   T               2   2               1   2
                  So, population after 2 years =  P 1 +  100    = 1,20,000 1 +  100    = 1,20,000 1 +  50 
                                                    
                                                                                                 
                                                                           
                                                    
                                                                           
                                                                                                 
                                                             51  2            51   51
                                                = 1,20,000    50    = 1,20,000 ×   50  ×  50   = 1,24,848
                Thus, the population of the town after 2 years will be 1,24,848.
                Example 31: In a laboratory, the count of bacteria in a certain experiment was increasing at the
                rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.
                Solution: Initial count of bacteria (P) = 5,06,000

                Rate of growth in the count of bacteria (R) = 2.5% per hour; Time (T) = 2 hours
                                                                                    .
                                                             R   n              25   2             1025  2
                So, the final count of bacteria (A) =  P1 +  100   = 5,06,000 1 +  100    = 5,06,000   1000
                                                        
                                                                              
                                                                                                           
                                                                
                                                        
                                                                              
                                                                  41   41
                                                    = 5,06,000 ×     ×     = 531616.25 ≈ 531616
                                                                  40   40
                Example 32: A scooter was bought for `42,000. Its value depreciated at the rate of 8% per annum.
                Find its value after 2 years.
                Solution: Cost of the scooter = `42,000; Rate of depreciation = 8% per annum
                                                                               8  2           23  23
                Therefore, value of the scooter after 2 years = `42,000 1 −    100   = `42,000  25  25    = `35,548.80.
                                                                          
                                                                                                    
                                                                                  
                                                                          
                                                                                               
                Example 33: Girish bought a shop for `4,60,000 in 2013. In 2014, its value increased by 4%. In
                2015, the value decreased by 5%. In 2016, it again increased by 10%. What will be the value of the
                shop in 2017?
                Solution: Let the value of the shop in 2017 be P. Given, initial value (P ) in 2013 = `4,60,000
                                                                                           1
                Increase in value in 2014 (R ) = 4%, Decrease in value in 2015 (R ) = 5%
                                              1
                                                                                     2
                Increase in value in 2016 (R ) = 10%
                                              3
                ∴     Value of the shop in 2017,
                                                                                                 5  
                                                                                                          10 
                                                                                        4  
                                                                  R 
                                                                                  
                                                        R  
                                         
                                              R  
                                  P =  P 1 +  100  1 −  100  1 +  100    = 4,60,000 1 +  100  1 −  100  1 +  100
                                                                    3
                                                1
                                                          2
                                                                                                             
                                                                                           
                                                                                                     
                                                                                  
                                        1 
                                                            
                                                  
                                         
                                                                                  
                                                                      1 
                                                     1  
                                                              1  
                                               
                                                                                                  11
                                    = 4,60,000 1 +  25  1 −  20  1 +  10    = 4,60,000 ×   26  ×  19  ×  10   = 4,99,928
                                                        
                                                                
                                               
                                               
                                                                                             20
                                                                                        25
                Thus, the value of shop in 2017 will be `4,99,928.
                         Practice Time 7E
                  1.  Calculate the amount and compound interest on
                    (a)  `5,000 for 2 years at 8% per annum, compounded annually.
                                     1
                    (b)  `10,000 for 1   years at 10% per annum, compounded half yearly.
                                     2
                    (c)  `18,000 for 1 year at 8% per annum, compounded quarterly.
                  2.  Neelam borrowed `50,000 from a bank to buy a computer at a rate of 15% p.a. compounded yearly.
                     What amount will she pay at the end of 2 years and 4 months to clear the loan?
                                                                  185                                 Comparing Quantities
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