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\ 06-Jan-2025 Bharat Arora Proof-7 Reader’s Sign _______________________ Date __________

1 1
Area of DABN = × AN × BN = × 80 m × 50 m = 2000 m 2
2 2
1 1
Area of EFMP = × (FM + EP) × MP = × (40 + 60) m × 110 m = 5500 m 2
2 2
1 1
Area of BCQN = × (QC + BN) × NQ = × (40 + 50) m × 80 m = 3600 m 2
2 2
∴ Area of the land = Area of polygon ABCDEF

= Area of DAMF + Area of DEPD + Area of DQCD + Area of DABN + Area of EFMP
+ Area of BCQN
= (600 + 1800 + 800 + 2000 + 5500 + 3600) m = 14300 m 2
2
Thus, the area of Raman’s land is 14300 m .
2

Practice Time 10C

1. Find the area of polygon ABCDEF as shown in the figure given below.
E 5 cm D

F C
6 cm 10 cm

A B
9 cm
2. Find the area of the following.
(a) regular hexagon (b) regular pentagon
D 17 cm A

E P C 5 cm

33 cm 17 cm B 8 cm E 9 cm
F O B
A C D
[Hint: In an isosceles D, the altitude from the vertex bisects the base.]

3. Find the area of the following polygons for which measurements are given.
(a) AD = 10 cm, AG = 8 cm, AH = 6 cm, and (b) TK = 20 m, KL = 30 m, LM = 30 m, and
AF = 3 cm. MR = 40 m.
C Q
B P
5 cm 7 cm 50 m 70 m
H D L A
A F G T K M R
3 cm 20 m

S B E
E 30 m
4. There is a pentagon-shaped park as shown in the figure. Find its area in two different
ways and show that the area in each case is the same. 15 m 15 m

C 15 m D

241 Mensuration