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E:\Working\Focus_Learning\Math_Genius-8\Open_Files\15_Chapter_11\Chapter_11
                 \ 06-Jan-2025  Bharat Arora   Proof-7             Reader’s Sign _______________________ Date __________





                Multiplicative Inverse or Reciprocals


                                                               1
                                                                    1
                                                                    −
                We know that reciprocal of an integer a is     a  =  a . Similarly, the reciprocal of a rational number
                  p           p  −1    q
                         1
                    is    p    or     or     .
                  q
                
                                 q
                                
                                         
                                          p
                         
                          q                            1  5  1
                                                    5
                                                                      –5
                For example, the reciprocal of (3)  =   =    3 5  = 3 .
                                                        
                                                         3
                Similarly, the reciprocal of   4  3  =  1  3  =   4  − 3  .
                                                              
                                               
                                                              5
                                               5
                                                             
                                              
                                                       4
                                                     
                                                      
                                                       5
                                                     
                The reciprocal is also known as the multiplicative inverse.
                Example 2: Find the reciprocal of
                                                           2
                           (a)  (–2) 5               (b)       − 3
                                                          
                                                           5
                                                        1      1
                                                  5
                Solution: (a)  Reciprocal of (–2)  =        =
                                                       − (  2) 5  − 32
                                                                        8
                                                                 2
                                                2
                           (b)  Reciprocal of      − 3  =   1  − 3  =      3  =  125
                                                                 5
                                                                
                                                5
                                               
                                                       
                                                         2
                                                        
                                                         5
                                                       
                                        (
                                                     1
                                          0
                Example 3: Simplify:  4 + ) ÷  2 0  0      − 2
                                                    
                                                     2
                                                          1
                                                                      1
                                                                                                           1
                           (
                                                     0
                                                                  0
                Solution:  4 + ) ÷  2 0  0   1 − 2  = ( 11) ÷      − 2  =  2 ×      =×  1  =  1      Q Q Reciprocal of      − 2  =   1  2 
                                                                           1
                             0
                                                 +
                                                                                                                    
                                        
                                                                                                          
                                       
                                                                                                           2
                                                                                                                   2
                                                                                                                  
                                        2
                                                                     
                                                        
                                                                      2
                                                          2
                                                                                   4
                                                                               4
                                                                                                                        
                                        (
                                                     1 
                                               −
                                                3
                Example 4: Simplify:  4 ×     2 ) ÷     10   − 2
                                          2
                                                                                  1 
                                          1 
                                                 
                                                       1 
                                                               1 
                           (
                                   3
                             2
                                  −
                Solution:  4 ×   2 ) ÷      10 − 2   =  16 ×  2   ÷     10 − 2  =     16 ×  1   ÷  10   − 2
                                                                
                                                        3 
                                                 
                                                                                
                                            
                                                 
                                                                            8
                                                                                
                                                      1   2  2    1
                                               = 2 ×  10   =  100  =  50
                                                    
                                                   q
                                           p
                                                           r
                                          x   r   x   p    x  q
                Example 5: Show that        x   ×  x   ×  x   = 1 .         Think and Answer
                                                   r 
                                           q 
                                                           p 
                                                         
                                                 
                                                                                                   –3
                                                                                1. Find the value of 6 .
                                             q
                                                     r
                                    x   r   x   p    x   q                                                   –20
                                     p
                Solution: LHS =      x   ×    x   ×    x               2.  Find the multiplicative inverse of 100  .
                                     q 
                                                     p 
                                             r 
                                                          )
                                       )  × (x
                                                 )  × (x
                                = (x p – q r  q – r p  r – p q
                                                                                                      mn
                                                                                               m n
                                = x pr – qr  × x qp – rp  × x rq – pq                     [Q(a )  = a ]
                                                                                                   n
                                = x pr – qr + qp – rp + rq – pq                           [Qa × a  = a m + n ]
                                                                                              m
                                = x = 1 (RHS)                                             [Qa  = 1]
                                   0
                                                                                              0
                                                                  267                                Exponents and Powers
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