Page 310 - Math_Genius_V1.0_C8_Flipbook

E:\Working\Focus_Learning\Math_Genius-8\Open_Files\17_Chapter_13\Chapter_13
\ 06-Jan-2025 Bharat Arora Proof-6 Reader’s Sign _______________________ Date __________

Chapter assessment
A. choose the correct option.

2
1. The factors of x – 9 are
(a) (x – 3), (x – 3) (b) (x + 3), (x – 3) (c) (x + 3), (x + 3) (d) (x – 9), (x – 9)
2
2
2. (x – y) – z is equal to
(a) (x – y – z)(x + y + z) (b) (x – y + z)(x – y – z) (c) (x + y – z)(x – y + z) (d) (x + y + z)(x + y + z)
2
3. The quotient of (–32x y) ÷ (–8xy) is
(a) 4xy (b) –4xy (c) –4x (d) 4x

4. The factorised form of 23xy – 46x + 54y – 108 is
(a) (23x + 54)(y – 2) (b) (23x + 54y)(y – 2)
(c) (23xy + 54y)(–46x – 108) (d) (23x + 54)(y + 2)

2
5. Which of these is not a factor of –51st ?
(a) –51st 2 (b) –3st (c) 7t (d) –17st
6. ab – cd + ad – bc = ...............
(a) (a – c)(b – d) (b) (a – c)(b + d) (c) (a – d)(b – c) (d) (c – a)(b – d)

2
7. m + 6m – 16 = ...............
(a) (m + 8)(m – 2) (b) (m – 8)(m – 2) (c) (m – 8)(m + 2) (d) None of these
2
8. 1 – 2mn – (m + n ) = ...............
2
(a) (1 + m + n)(1 – m – n) (b) (1 + m – n)(1 + m + n)
(c) (1 + m + n)(1 – m + n) (d) (1 + m – n)(1 – m + n)
B. Assertion and Reason type Questions.
In the following question, a statement of Assertion (A) is followed by a statement of Reason (R).
Choose the correct option.

(a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
(b) Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of
Assertion (A).
(c) Assertion (A) is true but Reason (R) is false.
(d) Assertion (A) is false but Reason (R) is true.

3
2
2
1. Assertion (A): On dividing (15a + 5a +10a) by (–5a), we get (–3a – a – 2) as quotient.
Reason (R): When the dividend and divisor have opposite signs, the quotient has the negative sign.
2
2
2. Assertion (A): (2x + 3y) – 12xy = 4x + 9y 2
2
Reason (R): Factorisation can also be done by the difference of squares i.e., a – b = (a + b)(a – b)
2
3
2
2 3
3. Assertion (A): The common factor of 4x y and 16x y is 4x y.
Reason (R): A common factor is a number that can be divided into two different numbers without
leaving a remainder.
2
2
4. Assertion (A): a(2b – 5c) = 4b a + 25ac + 10abc
2
2
2
Reason (R): (x – y) = x – 2xy + y 2
308