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            Example 11: Which of the following numbers is divisible by 2?

                       (a)  2029                 (b)  4086             (c)  3123              (d)  14357
            Solution: We know that a number is divisible by 2 only if its ones digit is even.
            So, option (b), i.e. 4086, is divisible by 2.

            Example 12: Check divisibility of the following numbers by 9 as well as 3.
                       (a)  8235                 (b)  9061             (c)  5712              (d)  8631

            Solution: (a)  Given number is 8235.
                        ∴  Sum of digits = 8 + 2 + 3 + 5 = 18, which is divisible 9.             Remember
                            Hence, 8235 is divisible by 9 as well as 3.                       Remember: If a number
                                                                                              x is divisible by another
                        (b)  Given number is 9061.                                            number y, then it is also
                        ∴  Sum of digits = 9 + 0 + 6 + 1 = 16, which is not a multiple of     divisible by each of the
                            9 and 3.                                                          factors of the number y.
                            Hence, 9061 is not divisible by 9 and 3.

                        (c)  Given number is 5712.
                        ∴  Sum of digits = 5 + 7 + 1 + 2 = 15, which is not divisible by 9 but divisible by 3.
                            So, 5712 is divisible by 3, but not by 9.

                       (d)  Given number is 8631.
                        ∴  Sum of digits = 8 + 6 + 3 + 1 = 18, which is divisible by both 9 and 3. Hence, 8631 is
                            divisible by both 9 and 3.

            Example 13: If 31y5 is a multiple of 3, where y is an even digit, what could be the value of y?
            Solution: Sum of the digits of number 31y5 = 3 + 1 + y + 5 = 9 + y
            The number is divisible by 3 if the sum of its digit, i.e., (9 + y) is divisible by 3.

            This is only possible when y = 0, 3, 6 or 9. But, since y is an even digit, the value of y could be 0 and 6.
            Example 14: If 30z6 is a multiple of 9, where z is an odd digit, what is the value of z?

            Solution: Sum of the digits of number 30z6 = 3 + 0 + z + 6 = 9 + z
            Hence, for the number to be divisible by 9, possible value of z is either 0 or 9.
            But, since z is an odd digit. Hence, the value of z = 9.

            Example 15: For what value of b, the following numbers are divisible by 11?
                       (a)  23b                  (b)  6b75

            Solution: We know that the difference between the sum of odd digits and the sum of even digits
            should be either 0 or a multiple of 11 for a number to be divisible by 11.

                       (a)  Sum of odd digits of the number 23b = 2 + b, sum of even digits = 3
                             So, difference = 2 + b –3 = b – 1
                            If b = 1, then difference = 1 – 1 = 0, which is divisible by 11.

                            If b = 12, then difference = 12 – 1 = 11, which is divisible by 11.
                            But, the value of b cannot be 12 as b is a single digit.

                            ∴ The value of b is 1.

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