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E:\Working\Orange_Education\TouchPad_Maths_4\Open_Files\Chap_04\Chap_04
\ 10-Nov-2025 Bharat Arora Proof-8 Reader’s Sign _______________________ Date __________
DiviSion by A 1-Digit DiviSor
example 1. Divide 943 by 5. 1 8 8 Q
Solution. 5 9 4 3
Step 1. Start dividing from the highest place. Since 9 > 5, divide 9 by 5. – 5
From the multiplication table, we have:
4 4
1 × 5 = 5, 2 × 5 = 10 – 4 0
10 > 9 > 5. So, write 1 in the hundreds place of the quotient
4 3
and 5 below 9. – 4 0
Step 2. Subtract 5 from 9 which gives 9 – 5 = 4. 3 R
Step 3. Bring down 4 next to 4. The new dividend is 44.
Again, 8 × 5 = 40, 9 × 5 = 45
45 > 44 > 40. So, write 8 in the tens place of the quotient and 40 below 44.
Step 4. Subtract 40 from 44. We have 44 – 40 = 4.
Step 5. Bring down 3 next to 4. We get the dividend 43.
Divide 43 by 5. The result is 8 with a remainder of 3. 1 8 8
So, quotient = 188, remainder = 3. × 5
Checking: Quotient × Divisor + Remainder = Dividend 9 4 0
188 × 5 + 3 = 943 + 3
Therefore, the division is correct. 9 4 3
example 2. Divide 456 by 6.
Solution.
Step 1. As 4 < 6, start with 45 as the dividend. 7 6 Q
From the multiplication table, we have: 6 4 5 6
7 × 6 = 42, 8 × 6 = 48 – 4 2
48 > 45 > 42. So, write 7 in the tens place of the quotient and
42 below 45. 3 6
Step 2. Subtract 42 from 45. This gives 45 – 42 = 3. – 3 6
Step 3. Bring down 6 just to the right side of 3. Now, the dividend 0 R
becomes 36.
Again, 6 × 6 = 36
Step 4. Write 36 below 36 and subtract.
36 – 36 = 0
So, quotient = 76, remainder = 0.
Checking: Quotient × Divisor + Remainder = Dividend 7 6
76 × 6 + 0 = 456 × 6
Therefore, the division is correct. 4 5 6
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