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Example 3. Divide 4366 by 3.

Solution. 1 4 5 5 Q
Step 1. 4 > 3. Divide 4 by 3. 3 4 3 6 6
– 3
We have the quotient 1 and remainder 1.
Step 2. Bring down 3 alongside the remainder 1, 1 3
making it 13. – 1 2

Step 3. Divide 13 by 3. We have the quotient 4 1 6
and remainder 1. – 1 5
Step 4. Bring down the third digit 6 next to the 1 6
remainder 1, making it 16. – 1 5

Step 5. Divide 16 by 3. We have the quotient 5 and remainder 1. 1 R
Step 6. Bring down the fourth digit 6 next to the remainder 1, making it 16.

Step 7. Divide 16 by 3. We have the quotient 5 and remainder 1. 1 4 5 5
So, the quotient is 1455 and the remainder is 1. × 3

Checking: Quotient × Divisor + Remainder = Dividend 4 3 6 5
1455 × 3 + 1 = 4366 + 1

Therefore, the division is correct. 4 3 6 6

Example 4. Divide the following:
a. 2748 ÷ 8 b. 5437 ÷ 6

Solution. a. 2748 ÷ 8 b. 5437 ÷ 6
3 4 3 Q
9 0 6 Q
8 2 7 4 8 6 5 4 3 7
– 2 4 If the number which you have – 5 4

3 4 brought down is smaller than
– 3 2 the divisor, put ‘zero’ in the 0 3
quotient just above the digit you – 0
2 8 have brought down. Read the 0 3 7
– 2 4 divisor ‘0’ times to proceed – 3 6

4 R with the division further. 1 R
So, Q = 343, R = 4. So, Q = 906, R = 1.
Checking: Checking:

Quotient × Divisor + Remainder = Dividend Quotient × Divisor + Remainder = Dividend
343 × 8 + 4 = 2748 906 × 6 + 1 = 5437

2744 + 4 = 2748 5436 + 1 = 5437
Therefore, the division is correct. Therefore, the division is correct.

64 Mathematics 4