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DiviDing A 4-Digit nUmber by A 2-Digit DiviSor

example 1. Divide 8976 by 15. 5 9 8 Q

Solution. 15 8 9 7 6
Step 1. Since 8 < 15, divide 89 by 15. – 7 5

Now, 15 × 5 = 75 and 15 × 6 = 90. 1 4 7
– 1 3 5
75 < 89 and 90 > 89
1 2 6
Thus, 15 goes into 89 five times. – 1 2 0

Write 5 just above 9 in the quotient and 75 below 89. 6 R

Step 2. Subtract 75 from 89 to get 14 as the remainder. Bring down 7 to make it 147.

Step 3. Divide 147 by 15. 15 goes into 147 nine times as 15 × 9 = 135 < 147.

Write 9 next to 5 in the quotient and 135 below 147.

Step 4. Subtract 135 from 147 to get 12 as the remainder. Bring down 6 to make it 126.
Step 5. Divide 126 by 15. 15 goes into 126 eight times as 15 × 8 = 120 < 126.

Write 8 next to 9 in the quotient and 120 below 126.

Step 6. Subtract 120 from 126 to get 6 as the remainder.

So, Quotient = 598, Remainder = 6.

Checking: Quotient × Divisor + Remainder = Dividend

598 × 15 + 6 = 8976

8970 + 6 = 8976

Therefore, the division is correct.

example 2. Divide 8709 by 24 and check your answer.

Solution. Here, Dividend = 8709 and Divisor = 24

By long division, we have: 3 6 2 Q

Quotient = 362, Remainder = 21 2 4 8 7 0 9
– 7 2 (24 × 3 = 72)
Checking: Quotient × Divisor + Remainder = Dividend
1 5 0
362 × 24 + 21 = 8709 – 1 4 4 (24 × 6 = 144)

8688 + 21 = 8709 6 9

8709 = 8709 – 4 8 (24 × 2 = 48)

Therefore, the division is correct. 2 1 R

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