Page 179 - Touchpad Mathematics_Ver1.0_C5
P. 179

E:\Working\Orange_Education\TouchPad_Maths-5\Open file\Maths_5_Chapter-07
                 \ 19-Nov-2025  Bharat Arora   Proof-9             Reader’s Sign _______________________ Date __________





                   2.  Complete the following table.

                                       Weight                Weight in smaller unit
                        a.            5 kg 42 g
                        b.                                            5190 g

                        c.          9 kg 500 g
                        d.          8 g 234 mg
                        e.                                           7234 mg

                        f.           6 kg 110 g

                   3.  Convert into kg and g.

                        a.  1375 g              b.  5264 g              c.  8000 g               d.  9200 g

                   4.  Convert:

                        a.  48 kg into g        b.  60 g into mg        c.  770 mg into cg       d.  1 kg 312 g into g
                  5.  fill in the blanks.

                        a.  5324 mg = _____ g _____ mg                  b.  5 kg 3 g = _____ g
                        c.  3260 g = ____ kg ____ g                     d.  1999 g = ____ kg ____ g

                  6.  using 1 quintal = 100 kg and 1 tonne = 10 quintals = 1000 kg, fill in the blanks.

                        a.  5000 kg = ______ tonnes
                        b.  6850 kg = ______ tonnes ______ quintals ______ kg
                        c.  ______ kg = 12 tonnes
                        d.  8560 kg = ______ quintals ______ kg



                oPERATIonS on WEIGhT (MASS)

                Example 1. Add 15 kg 500 g, 21 kg 340 g and 5 kg 250 g.                                kg         g
                Solution.                                                                             1 5      5 0 0

                  Method 1.  We  write  the  given  weights  one below  the other  in                 2 1      3 4 0
                             such a way that  the same  units  are placed  in the                  +     5     2 5 0
                             same column (kg under kg, g under g, etc.) and then                      4 2      0 9 0
                             add as usual.

                             Thus, the answer is 42 kg 90 g.

                Method 2. Convert the weights into grams and add them.                                1 5 5 0 0 g
                                15 kg  500 g  =  15000 +  500  =  15500 g                             2 1 3 4 0 g
                                21 kg  340 g  =   21000 +  340  =  21340 g                         +     5 2 5 0 g

                                 5 kg  250 g  =   5000 +  250  =  5250 g                              4 2 0 9 0 g
                              Thus, the answer is 42090 g = 42000 g + 90 g = 42 kg 90 g.



                                                                                                             177
                                                                                             Measurement
   174   175   176   177   178   179   180   181   182   183   184