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example 2. Find the perimeter of a rectangle whose length is 10 cm and breadth is 5 cm.

Solution. Length of the rectangle = 10 cm and breadth of the rectangle = 5 cm

Perimeter of the rectangle = 2(Length + Breadth)

= 2(10 + 5) cm

Solve the = 2 × 15 cm
brackets first.
= 30 cm

Hence, the perimeter of the rectangle is 30 cm.

example 3. A park is 156 m long and 112 m wide. Abhi jogs around it six times. How

much distance does he cover?

Solution. Length of the park = 156 m and breadth of the park = 112 m

Perimeter of the park = 2(Length + Breadth)

= 2(156 + 112) m

= 2 × 268 m

= 536 m

So, distance covered by Abhi in 1 round = 536 m

Distance covered by Abhi in 6 rounds = (6 × 536) m
= 3216 m

Hence, Abhi covers 3216 m in 6 rounds.
example 4. Find the cost of fencing a rectangular park that is 125 m long and 75 m

broad at the rate of `35 per metre.

Solution. Length of the park = 125 m and breadth of the park = 75 m

Perimeter of the park = 2(Length + Breadth)

= 2(125 + 75) m

= 2 × 200 m = 400 m

Length of the fence = 400 m

Cost of fencing = `(400 × 35)

= `14,000

Hence, the cost of fencing the park is `14,000.

190 Mathematics 5