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Hexadecimal equivalent of 10001111.0111 is
1
3
0
2
1000 1111 . 0111 8(2 ) 4(2 ) 2(2 ) 1(1 ) Hexa
8 F . 7 1 0 0 0 1 × 8 + 0 × 4 + 0 × 2 + 0 × 1 = 8
1 1 1 1 1 × 8 + 1 × 4 + 1 × 2 + 1 × 1 = 15
0 1 1 1 0 × 8 + 1 × 4 + 1 × 2 + 1 × 1 = 7
(217.34) = (8F.7)
8 16
12. Convert (C1D.B) to octal.
16
Ans.
C(12) 1 D . B
1100 0001 1101 . 1011
Binary equivalent is (110000011101.1011)
2
Converting 110 000 011 101.101 100 to octal
1
2
0
110 000 011 101 . 101 100 4(2 ) 2(2 ) 1(1 ) Octal
6 0 3 5 . 5 4 1 1 0 1 × 4 + 1 × 2 + 0 × 1 = 6
0 0 0 0 × 4 + 0 × 2 + 0 × 1 = 0
0 1 1 0 × 4 + 1 × 2 + 1 × 1 = 3
1 0 1 1 × 4 + 0 × 2 + 1 × 1 = 5
1 0 0 1 × 4 + 0 × 2 + 0 × 1 = 4
(6035.54)
8
13. Perform the following Binary addition.
(1001.1) + (110110.11) + (10.1) 2
2
2
Ans. +1 +1 +1 +1 +1 +1 +1
1 0 0 1 . 1
1 1 0 1 1 0 . 1 1
+ 1 0 . 1
1 0 0 0 0 1 0 . 1 1
(1000010.11) 2
14. Perform binary subtraction (100110.01) - (10111.1) using.
2
2
a. Borrow method
b. 1’s Complement method
c. 2’s Complement method
Ans. a. +1 +1 +1 +1 +1 +1
1 0 0 1 1 0 -1 . 0 1
- 1 0 1 1 1 . 1
0 0 1 1 1 0 . 1 1
Discarding leading 0’s
(1110.11) 2
b. 1’s complement of 010111.10 is 101000.01 +1 +1
Adding 100110.01 and 101000.01, we get 1 0 0 1 1 0 . 0 1
Discarding MSB 1 and leading 0’s + 1 0 1 0 0 0 . 0 1
1 0 0 1 1 1 0 . 1 0
1
(1110.11) 2 0 0 1 1 1 0 . 1 1
4040 Touchpad Computer Science-XI

